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3 years ago

What are salt ? How they are used

Chemistry

1 answer:

Leno4ka [110]3 years ago

7 0

There is different types of salt.
1)table salt
2)lime salt

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Use Boyle’s law to complete the following:

mixas84 [53]

Answer:

The answer to your question is: 0.25 l

Explanation:

Data

P1 = 1 atm

V1 = 0.5 l

P2 =2 atm

V2 = ?

T = constant

Formula

V1P1 = V2P2

Clear V2 from the formula

V2 = V1P1/P2

Substitution

V2 = (0.5)(1)/2 substitution

= 0.25 l result

3 0

3 years ago

Isotonic compound have high melting point. Why ? Name the ions present in CaS.

yuradex [85]

Explanation:

Because a large amount of energy is required to break the strong inter-ionic attraction.

CaS => Ca2+ & S2-

3 0

3 years ago

What is uranium classified as

Free_Kalibri [48]

Answer:

uranium is classifide as actinide a chemical element atomic number 92 and is a solid at room temperature

7 0

3 years ago

The solubility of silver(I)phosphate at a given temperature is 1.02 g/L. Calculate the Ksp at this temperature. After you get yo

Snezhnost [94]

<u>Answer:</u> The solubility product of silver (I) phosphate is $9.57\times 10^{-10}$

<u>Explanation:</u>

We are given:

Solubility of silver (I) phosphate = 1.02 g/L

To convert it into molar solubility, we divide the given solubility by the molar mass of silver (I) phosphate:

Molar mass of silver (I) phosphate = 418.6 g/mol

$\text{Molar solubility of silver (I) phosphate}=\frac{1.02g/L}{418.6g/mol}=2.44\times 10^{-3}mol/L$

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The chemical equation for the ionization of silver (I) phosphate follows:

$Ag_3PO_4(aq.)\rightleftharpoons 3Ag^{+}(aq.)+PO_4^{3-}(aq.)$

3s s

The expression of $K_{sp}$ for above equation follows:

$K_{sp}=(3s)^3\times s$

We are given:

$s=2.44\times 10^{-3}M$

Putting values in above expression, we get:

$K_{sp}=(3\times 2.44\times 10^{-3})^3\times (2.44\times 10^{-3})\\\\K_{sp}=9.57\times 10^{-10}$

Hence, the solubility product of silver (I) phosphate is $9.57\times 10^{-10}$

4 0

3 years ago

I need help with this pls help !!

Doss [256]

Answer:

70g of HCl

Check the attachment below. Locate 25C and then follow the line where it meets the curve.

4 0

3 years ago