What are salt ? How they are used

A 50 kg cart has 324 kg•m/s of momentum. How fast is the cart going?

PilotLPTM [1.2K]

Answer: 6.48m/s

Explanation:

From the question given, we obtained the following:

M = 50 kg

Velocity =?

Momentum = 324 kg•m/s

Momentum = Mass x Velocity

Velocity = momentum /Mass

Velocity = 324 / 50

Velocity = 6.48m/s

5 0

3 years ago

The weight of the buggy was 40N on Mars. When the buggy landed on Mars it rested on an area of 0.025 m2. Calculate the pressure

elena-s [515]

Answer:

The pressure exerted by the buggy on the surface of Mars is 1600 pascals.

Explanation:

The pressure is determined by the definition of stress, which is the force exerted by the buggy on the martian surface divided by the contact area of the latter:

$\sigma = \frac{F}{A}$

Where:

$\sigma$ - Stress, measured in pascals.

$F$ - Force, measured in newtons.

$A$ - Area, measured in square meters.

The force is the weight of the buggy (40 N) and $A = 0.025\,m^{2}$ , the stress is now calculated:

$\sigma = \frac{40\,N}{0.025\,m^{2}}$

$\sigma = 1600\,Pa$

The pressure exerted by the buggy on the surface of Mars is 1600 pascals.

4 0

3 years ago

Which law is described by saying that when the pressure of a gas in a sealed container is cut in half, the gas will double in vo

Anon25 [30]

I believe it would be Boyle's Law

(P [is proportional to] 1/V)

P being pressure

V being volume

4 0

3 years ago

Read 2 more answers

An important reaction in the formation of photochemical smog is the photodissociation of NO2: NO2 + hv >>> NO(g) + O(g)

vaieri [72.5K]

Explanation:

$NO_2 + hv\rightarrow NO(g) + O(g)$

The maximum wavelength of light that can cause this reaction is 420 nm.

a) The wavelength given lies in the range of visible light range that is from 400 nano meters to 700 nano meters.

The light with wavelength of 420 nm is found in the range of visible light.

b)The maximum strength of a bond :

$E=\frac{h\times c}{\lambda}$

where,

E = energy of photon = Energy required to break single molecule of nitrogen dioxide

h = Planck's constant = $6.626\times 10^{-34}Js$

c = speed of light = $3\times 10^8m/s$

$\lambda$ = wavelength = $420 nm=420\times 10^{-9}m$

$E=\frac{6.626\times 10^{-34}Js\times 3\times 10^8 m/s}{420\times 10^{-9}m}$

$E=4.733\times 10^{-19} J$

Energy required to break 1 mole of nitrogen dioxide molecules:

$= E\times N_A=4.733\times 10^{-19} J\times 6.022\times 10^{23} mol^{-1}$

$=285,012.66 J/mol=285.13 kJ/mol$

(1 J = 0.001 kJ )

285.13 is the maximum strength of a bond, in kJ/mol, that can be broken by absorption of a photon of 420-nm light.

c) the photodissociation reaction showing Lewis-dot structures is given in an image attached.

6 0

4 years ago

A dehydration reaction starting with 3.0 g cyclohexanol produces 1.9 g cyclohexene. Calculate the theoretical yield for this rea

Ilya [14]

Answer:

77%

Explanation:

First we convert 3.0 g of cyclohexanol (C₆H₁₂O) to moles, using its molar mass:

Molar mass of C₆H₁₂O = 100.158 g/mol

3.0 g ÷ 100.158 g/mol = 0.030 mol

Then we convert 1.9 g of cyclohexene (C₆H₁₀) to moles, using its molar mass:

Molar mass of C₆H₁₀ = 82.143 g/mol

1.9 g ÷ 82.143 g/mol = 0.023 mol

Finally we calculate the theoretical yield:

0.023 mol / 0.030 mol * 100% = 77%

3 0

3 years ago