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poizon [28]
3 years ago
12

A road is 2/5 of a mile long. A crew needs to repave 4/5 of it. How long is the section that needs to be repaved?

Mathematics
1 answer:
yanalaym [24]3 years ago
6 0

the answer is 2/20 or simplified 1/10

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Determine the number of x-intercepts that appear on a graph of each function. f (x) = (x - 6)2(x + 2)2
Tpy6a [65]
<span>The number of x-intercepts that appear on the graph of  the function
</span>f(x)=(x-6)^2(x+2)^2 is two (2): x=6 (multiplicity 2) and x=-2 (multiplicity 2)


Solution
x-intercepts:
f(x)=0→(x-6)^2 (x+2)^2 =0

Using that: If a . b =0→a=0 or b=0; with a=(x-6)^2 and b=(x+2)^2

(x-6)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x-6)^2] = sqrt(0)→x-6=0
Adding 6 both sides of the equation:
x-6+6=0+6→x=6 Multiplicity 2

(x+2)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x+2)^2] = sqrt(0)→x+2=0
Subtracting 2 both sides of the equation:
x+2-2=0-2→x=-2 Multiplicity 2
6 0
3 years ago
Read 2 more answers
Can someone help me
DiKsa [7]

Answer:

23.27 - 5. 3 = 17.97

Step-by-step explanation:

6 0
3 years ago
I have 7 hundreds blocks, 5 tens blocks, and 8 ones blocks. I use my blocks to model two 3-digit numbers. What could my two numb
kompoz [17]
Thought about it and theres a couple of others but i'm going to say 424-334
7 0
3 years ago
What is the answer to 2/3 (5x – 5) = 10 because i don't know it
mars1129 [50]

Answer:

x = 76/75

Step-by-step explanation:

7 0
3 years ago
A spherical hot air balloon has a diameter of 55 feet when the balloon is inflated the radius increases at a rate of 1.5 feet pe
Nuetrik [128]

Answer: 46.90mins

Step-by-step explanation:

The given data:

The diameter of the balloon = 55 feet

The rate of increase of the radius of the balloon when inflated = 1.5 feet/min.

Solution:

dr/dt = 1.5 feet per minute = 1.5 ft/min

V = 4/3·π·r³

The maximum volume of the balloon

= 4/3 × 3.14 × 55³

= 696556.67 ft³

When the volume 2/3 the maximum volume

= 2/3 × 696556.67 ft³

= 464371.11 ft³

The radius, r₂ at the point is

= 4/3·π·r₂³

= 464371.11 ft³

r₂³ = 464371.11 ft³ × 3/4

= 348278.33 ft³

348278.333333

r₂ = ∛(348278.33 ft³) ≈ 70.36 ft

The time for the radius to increase to the above length = Length/(Rate of increase of length of the radius)

The time for the radius to increase to the

above length

Time taken for the radius to increase the length.

= is 70.369 ft/(1.5 ft/min)

= 46.90 minutes

46.90mins is the time taken to inflate the balloon.

5 0
3 years ago
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