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amid [387]
3 years ago
9

A construction crew built 9 3/4 miles of road in 4 1/2 days. What is the unit rate in miles per day

Mathematics
2 answers:
nignag [31]3 years ago
8 0

Answer:

2 1/6 miles per day

Step-by-step explanation:

9 and 3/4 divided by 4 and 1/2 =2 and 1/6

Which means the crew moves

2 and 1/6 of a mile per day

Oxana [17]3 years ago
4 0

Answer:

2⅙ miles per day

Step-by-step explanation:

Miles : Days

39/4 = 9¾ : 4½ = 9/2

X : 1

39/4 ÷ 9/2 = X/1

39/4 × 2/9 = X

13/6 = X

X = 2⅙

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Find the ninth term of the sequence sqrt 5, sqrt 10, ^2sqrt 5
hjlf
The rule of geometric sequence is   ⇒⇒⇒ a * r^(n-1)
Where a is the first term and  r is the common ratio
for the given sequence  √5 , √10 , 2√5 , .......
a = √5
r = √10 / √5 = √2
The ninth term = √5 * (√2)^(9-1) = √5 * (√2)⁸ = 16 √5

the correct answer is the third option 16√5
5 0
3 years ago
Katie bought 3 pounds of peaches for $5.70 last week. This week, they are $1.88 per pound. Is this week’s rate proportional to l
netineya [11]

Answer:

1.9

Step-by-step explanation:

Step by step answer

5 0
3 years ago
Read 2 more answers
Select the expression in terms of n
Bumek [7]

Answer:

2n - 11

Step-by-step explanation:

Note there is a common difference d between consecutive terms of the sequence, that is

d = - 7 - (- 9) = - 5 - (- 7) = - 7 + 9 = - 5 + 7 = 2

This indicates the sequence is arithmetic with n th term

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 9 and d = 2, thus

a_{n} = - 9 + 2(n - 1) = - 9 + 2n - 2 = 2n - 11

6 0
2 years ago
What’s the best way to revise for maths? can never remember how to do anything.
Allisa [31]

Repetition is a guaranteed way to learn something. If it is a formula you need to learn, try doing flashcards and reading it over and over again until you can spell it without the flahcard. If it is something like factoring, just do a bunch of factoring problems until you get the feel of it.

8 0
3 years ago
Look at picture. Does anybody know the answer I’m lost?
masha68 [24]

Let x,y be the dimensions of the rectangle. We know the equations for both area and perimeter:

A=xy=36

P=2(x+y)=36 \iff x+y=18

So, we have  the following system:

\begin{cases}xy=36\\x+y=18\end{cases}

From the second equation, we can deduce

y=18-x

Plug this in the first equation to get

xy=x(18-x)=-x^2+18=36

Refactor as

x^2-18x+36=0

And solve with the usual quadratic formula to get

x=9\pm3\sqrt{5}

Both solutions are feasible, because they're both positive.

If we chose the positive solution, we have

x=9+3\sqrt{5} \implies y=18-x=18-9-3\sqrt{5}=9-3\sqrt{5}

If we choose the negative solution, we have

x=9-3\sqrt{5} \implies y=18-x=18-9+3\sqrt{5}=9+3\sqrt{5}

So, we're just swapping the role of x and y. The two dimensions of the rectangle are 9+3\sqrt{5} and 9-3\sqrt{5}

6 0
2 years ago
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