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dimulka [17.4K]
3 years ago
14

A student is given an assignment to demonstrate diffraction. He takes a photograph of a straw in a glass of water. The straw app

ears bent at the water level. Which best describes this example?
A) This is a good example of diffraction.
B) This is an example of dispersion and not diffraction.
C) This is an example of refraction and not diffraction.
D) This is an example of reflection and not diffraction.
Physics
2 answers:
arlik [135]3 years ago
8 0

The answer is "c". because the straw the straw moves from air to water and appears refracted at the water level

wel3 years ago
7 0

The answer is C, This is an example of refraction and not diffraction.

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A stone is dropped from the edge of a roof. find the distance travelled by the stone in 2sec after its release.
Lena [83]
S = ?
U = 0
V = ?
A = 9.81
T = 2

we tryna find s

lets use s = ut + (at^2)/2
ut cancels out since u = 0
(at^2)/2 = (9.81 x 2^2)/2
= 19.62m
3 0
3 years ago
A block of mass 12.2 kg is sliding at an initial velocity of 6.65 m/s in the positive x-direction. The surface has a coefficient
valentina_108 [34]

Explanation:

Given that,

Mass of the block, m = 12.2 kg

Initial velocity of the block, u = 6.65 m/s

The coefficient of kinetic friction, \mu_k=0.253

(a)The force of kinetic friction is given by :

f=\mu_k mg

mg is the normal force

So,

f=0.253\times 12.2\times 9.8\\\\f=30.24\ N

(b) Net force acting on the block in the horizontal direction,

f = ma

a is the acceleration of the block

a=\dfrac{f}{m}\\\\a=\dfrac{30.24}{12.2}\\\\a=2.47\ m/s^2

(c) Let d is the distance covered by the block before coming to the rest. Using third equation of motion as follows :

v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{-(6.65)^2}{2\times 2.47}\\\\d=-8.95\ m

Hence, this is the required solution.

3 0
3 years ago
A wheel 30 cm in diameter accelerates uniformly from 245 rpm to 380 rpm in 6.1 s . Part A How far will a point on the edge of th
jonny [76]

Answer:

A point on the edge of the wheel will travel 199.563 radians at the given time.

Explanation:

Given;

initial angular velocity of the wheel; \omega _i = 245 \ rev/\min = 245\ \frac{rev}{\min} \times \frac{2\pi}{1\  rev} \times \frac{1 \ \min}{60 \ s} = 25.66 \ rad/s

final angular velocity of the wheel;

\omega _f = 380 \ rev/\min = 380 \ \frac{rev}{\min} \times \frac{2\pi}{1\  rev} \times \frac{1 \ \min}{60 \ s} = 39.80 \ rad/s

radius of the wheel, d/2 = (30 cm ) / 2 = 15 cm = 0.15 m

time of motion, t = 6.1 s

The angular distance traveled by the edge of the wheel is calculated as;

\theta = (\frac{\omega_f + \omega_i}{2} )t\\\\\theta =  (\frac{39.8 + 25.66}{2} )\times 6.1\\\\\theta = 199.653 \ radian

Therefore, a point on the edge of the wheel will travel 199.563 radians at the given time.

6 0
3 years ago
What is the mass of 294N weight on Earth
STALIN [3.7K]

Answer:

m=30kg

Explanation:

F=mg

294=m(9.8)

m=294/9.8

m=30kg

Hope that helps :)

7 0
4 years ago
Larry and Balky set up an experiment to analyze the motion of a marble as it rolled down an incline. They started the marble at
erik [133]

Answer:

Option A is the correct answer.

Explanation:

The instantaneous acceleration = Change in velocity in velocity/Time taken

The slope of the graph should give instantaneous acceleration.

  Slope of a graph = Change in value of Y -axis / Change in values of X -axis

 Comparing both the equations

   Change in value of Y -axis = Change in velocity in velocity

   Change in values of X -axis = Time taken

So velocity values should be on the Y axis and Time values should be on the X axis.

Option A is the correct answer.


7 0
3 years ago
Read 2 more answers
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