Answer:
The magnitude of the frictional force is
Explanation:
From the question we are told that
The force exerted on the box is
Generally for the box to remain at rest then it means that the frictional force is greater than or equal to the force applied to move it i.e
=>
The dimensions of the rectangle are:
l = 50 m
b = m
The perimeter is the length of the outline of a shape. To find the perimeter of a rectangle or square you have to add the lengths of all the four sides.
<h3>How do we find a perimeter of a rectangle?</h3>The perimeter of a rectangle,denoted by P is given by the formula, P=2l+2b, where l is the length and b is the breadth of the rectangle.
<h3>Given:</h3>As per the question:
Perimeter of the room is given as P = 200 m
The region is rectangular having a semicircle at each end.
Now,
Let 'l' be the length of the rectangle, 'b' be its breadth and 'r' be the radius of the semi-circle at each end.
Then, Area of the given rectangle, A = lb
Perimeter of the room, P is =
Therefore,
Now,
Area, A =
Now, differentiate A w.r.t l:
Again differentiating w.r.t 'l', we get:
< 0
Thus we get maximum are when
Therefore,
l = 50 m
Now, from
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