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CaHeK987 [17]
3 years ago
10

Squid and Octolules are propelled by expelting water, which is maintained in a body cavity. A squid of 6.5 kg (including water i

n the cavity) is at rest, when suddenly a predator is spotted.
A) If the squid has 1.6 kg of water in its cavity, how fast should it expel this water so that it reaches 2.5 m/s and escapes the predator? What is the kinetic energy of the squid after this maneuver?

Physics
1 answer:
Elina [12.6K]3 years ago
4 0

Answer:

see attachment

Explanation:

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Sallys physical education teacher timed her run and recorded the time and distance in the table below. What is her average speed
Fudgin [204]
Answer: B) 2.5 m/s

Explanation: Find the average of the time and distance, and see how far they go in only 1 second.


1 + 2 + 3 + 4 + 5 = 15
15 divided by 5 = 3

3 seconds

2 + 5 + 7 + 10 + 12 = 36
36 divided by 5 = 7.2


7.2m per 3 seconds.

7.2 divided by 3 = 2.4

Therefore, the answer is technically 2.4m/s
4 0
3 years ago
Can someone give me an example or explanation of calculating energy from voltage? Many thanks!
antoniya [11.8K]
Expression to calculate energy from voltage: E= V*Q where E= energy, V= voltage, and Q= charge

Additional help:
-To find the Voltage ( V )
[ V = I x R ] V (volts) = I (amps) x R (Ω)

-To find the Current ( I )
[ I = V ÷ R ] I (amps) = V (volts) ÷ R (Ω)

-To find the Resistance ( R )
[ R = V ÷ I ] R (Ω) = V (volts) ÷ I (amps)

I hope that helps to some extent-
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2 years ago
why can scientists ignore the forces of attraction between particles in a gas under ordinary conditions?
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<span>The particles in a gas are apart and moving fast, so the forces of attraction are too weak to have a noticeable effect.</span>
5 0
3 years ago
Read 2 more answers
According to the equation for the Balmer line spectrum of hydrogen, a value of n = 3 gives a red spectral line at 656.3 nm, a va
nirvana33 [79]

Answer:

E3 = 3.03 10⁻¹⁶ kJ,  E4 = 4.09 10⁻¹⁶ kJ and  E5 = 4.58 10⁻¹⁶ kJ

Explanation:

They give us some spectral lines of the Balmer series, let's take the opportunity to place the values in SI units

     n = 3        λ = 656.3 nm = 656.3 10⁻⁹ m

     n = 4        λ = 486.1 nm = 486.1 10⁻⁹ m

     n = 5        λ=434.0 nm = 434.0 10⁻⁹ m

Let's use the Planck equation

     E = h f

The speed of light equation

   c = λ f

replace

    E = h c /λ

Where h is the Planck constant that is worth 6.63 10⁻³⁴ J s and c is the speed of light that is worth 3 10⁸ m / s

Let's calculate the energies

     E = 6.63 10⁻³⁴ 3 10⁸ / λ

     E = 19.89 10⁻²⁶ /λ

n = 3

    E3 = 19.89 10⁻²⁶ / 656.3 10⁻⁹

    E3 = 3.03 10⁻¹⁹ J

    1 kJ = 10³ J

    E3 = 3.03 10⁻¹⁶ kJ

n = 4

    E4 = 19.89 10⁻²⁶ /486.1 10⁻⁹

    E4 = 4.09 10⁻¹⁹ J

    E4 = 4.09 10⁻¹⁶ kJ

n = 5

    E5 = 19.89 10⁻²⁶ /434.0 10⁻⁹

    E5 = 4.58 10⁻¹⁹ J

    E5 = 4.58 10⁻¹⁶ kJ

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3 years ago
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3 years ago
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