Squid and Octolules are propelled by expelting water, which is maintained in a body cavity. A squid of 6.5 kg (including water i
n the cavity) is at rest, when suddenly a predator is spotted.
A) If the squid has 1.6 kg of water in its cavity, how fast should it expel this water so that it reaches 2.5 m/s and escapes the predator? What is the kinetic energy of the squid after this maneuver?
A) If the squid has 1.6 kg of water in its cavity, how fast should it expel this water so that it reaches 2.5 m/s and escapes the predator? What is the kinetic energy of the squid after this maneuver?
1 answer:
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Answer:
a = 1 m/s² and
Explanation:
The first two parts can be seen in attachment
We use Newton's second law on each axis
Y axis
Ty - W = 0
Ty = w
X axis
Tx = m a
With trigonometry we find the components of tension
Sin θ = Ty / T
Ty = T sin θ
Cos θ = Tx / T
Tx = T cos θ
We calculate the acceleration with kinematics
Vf = Vo + a t
a = (Vf -Vo) / t
a = (20 -10) / 10
a = 1 m/s²
We substitute in Newton's equations
T Sin θ = mg
T cos θ = ma
We divide the two equations
Tan θ = g / a
θ = tan⁻¹ (g / a)
θ = tan⁻¹ (9.8 / 1)
θ = 84º
We see that in the expression of the angle the mass does not appear therefore you should not change the angle
