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Bumek [7]
3 years ago
15

Who can help me ? please​

Mathematics
2 answers:
yarga [219]3 years ago
8 0

Answer:

Step-by-step explanation:

\frac{2x3}{3x3} \\

multiplying by three because you want the denominator same as the other.

  \frac{6}{9}

+ \frac{1}{9}

Add the numerators and keep the denominator the same - the denominator never gets added by the way. You only multiply them to get the denominators to equal

\frac{7}{9}

Masja [62]3 years ago
4 0

Answer:

\dfrac{7}{9}

Step-by-step explanation:

\dfrac{2}{3}=\dfrac{2\cdot 3}{3\cdot 3}=\dfrac{6}{9} \\\\\\\dfrac{6}{9}+\dfrac{1}{9}=\dfrac{7}{9}

Hope this helps!

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What are the excluded values of x for
ss7ja [257]

Answer:

x = - 2, x = 9

Step-by-step explanation:

Given

f(x) = \frac{x^2-9x}{x^2-7x-18}

The denominator of f(x) cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the values that x cannot be.

x² - 7x - 18 = 0

(x - 9)(x + 2) = 0

Equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

x - 9 = 0 ⇒ x = 9

The excluded values are x = - 2, x = 9

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3 years ago
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Compute delta y/delta x for the interval [2,5], where y = 4x - 9.
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