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aivan3 [116]
3 years ago
6

The cooking club made some pies to sell at a basketball game to raise money for the new books. The cafeteria contributed four pi

es to the sale. Each pie was then cut into into five pieces and sold. There were a total of 60 pieces to sell. How many pies did the club make?
Mathematics
2 answers:
cluponka [151]3 years ago
5 0
The answer is 12 pies
BabaBlast [244]3 years ago
5 0

Answer:

3

Step-by-step explanation:

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In which quadrant is the number 6 – 8i located on the complex plane?
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A concession stand at an athletic event is trying to determine how much to sell cola and iced tea for in order to maximize reven
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Solution :

Demand for cola : 100 – 34x + 5y

Demand for cola : 50 + 3x – 16y

Therefore, total revenue :

x(100 – 34x + 5y) + y(50 + 3x – 16y)

R(x,y)  = $100x-34x^2+5xy+50y+3xy-16y^2$

$R(x,y) = 100x-34x^2+8xy+50y-16y^2$

In order to maximize the revenue, set

$R_x=0, \ \ \ R_y=0$

$R_x=\frac{dR }{dx} = 100-68x+8y$

$R_x=0$

$68x-8y=100$  .............(i)

$R_y=\frac{dR }{dx} = 50-32x+8y$

$R_y=0$

$8x-32y=-50$  .............(ii)

Solving (i) and (ii),

4 x (i)    ⇒       272x - 32y = 400

     (ii)   ⇒   (-<u>)     8x - 32y = -50   </u>

                        264x        = 450

∴   $x=\frac{450}{264}=\frac{75}{44}$

     $y=\frac{175}{88}$

So, x ≈  $ 1.70      and    y = $ 1.99

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Thus, 1.70 dollars per cola

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Maximum revenue = $ 134.94

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