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2 years ago

12

if the following shapes are similar in find the measurement of the missing length G? Type a result in the empty box provided bel

ow

1 answer:

katrin [286]2 years ago

3 0

Answer:

okay my fellow bloke youmeasure the angle of thwe 69bilateralmum weight check

Step-by-step explanation:

1)vibe check =69

2)big man bloke ethan slayetr 69

3)yomam

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An art gallery sells paintings at 0.35 per square inch. if a painting is 2 feet 3 inches by 3 feet 5 inches. how much would the

Natalka [10]

Hello!

ANSWER

The painting would cost $387.45.

____________________________________________________________

EXPLANATION

2' 3" = 27"

3' 5" = 41"

Multiply the length by the width (in inches) of the painting.

27 * 41 = 1107

We now know that the area of the painting is 1107 $in.^{2}$ Next, multiply the cost per square inch (0.35) by the total amount of square inches (1107).

.35 * 1107 = 387.45

7 0

2 years ago

How to do number 13 and 14

Murrr4er [49]

From the information: v is 64 while c is 5

Differentiate the new equation h=-16 $t^{2}$ + 64t + 5 to get $\frac{dh}{dt}$ = -32t + 64.

no 13). At maximum height this derivative equals zero so: -32t + 64 = 0; -32t = -64; t=2.Hence ans is 2 secs

no 14). put t as 2 sec in the equation: h=-16 $t^{2}$ + 64t + 5. This gives

h=-16( $2^{2}$ ) + 64(2) + 5; h=-64+128+5=69. Hence h is 69ft

7 0

3 years ago

A bucket that weighs 6 lb and a rope of negligible weight are used to draw water from a well that is 80 ft deep. The bucket is f

zaharov [31]

Answer:

3200 ft-lb

Step-by-step explanation:

To answer this question, we need to find the force applied by the rope on the bucket at time $t$

At $t=0, the weight of the bucket is 6+36=42 \mathrm{lb}$

After $t$ seconds, the weight of the bucket is $42-0.15 t \mathrm{lb}$

Since the acceleration of the bucket is the force on the bucket by the rope is equal to the weight of the bucket.

If the upward direction is positive, the displacement after $t$ seconds is $x=1.5 t$

Since the well is 80 ft deep, the time to pull out the bucket is $\frac{80}{2}=40 \mathrm{~s}$

We are now ready to calculate the work done by the rope on the bucket.

Since the displacement and the force are in the same direction, we can write

$W=\int_{t=0}^{t=36} F d x$

Use $x=1.5 t$ and $F=42-0.15 t$

$W=\int_{0}^{36}(42-0.15 t)(1.5 d t)$

$=\int_{0}^{36} 63-0.225 t d t$

$=63 \cdot 36-0.2 \cdot 36^{2}-0=3200 \mathrm{ft} \cdot \mathrm{lb}$

$=\left[63 t-0.2 t^{2}\right]_{0}^{36}$

$W=3200 \mathrm{ft} \cdot \mathrm{lb}$

4 0

2 years ago

Jake traces a regular octagon on his paper. Each side measures 6 centimeters. He also traces a regular decagon on his paper. Eac

ivolga24 [154]

Answer:

10centimers

Step-by-step explanation:

3 0

3 years ago

The ratio of gifts wrapped in red to gifts wrapped in green is 3:5. If there are 32 total gifts, how many of each are wrapped in

QveST [7]

Answer:

Step-by-step explanation:

This is probably pretty late, but I'll do it anyway.

There are 8 parts all together.

3x + 5x = 32 Combine the terms on the left.

8x = 32 Divide by 8

8x = 32/8

x = 4

Therefore the red gifts are 3*4 = 12

The green gifts are <u> 5*4 = 20</u>

Total 32 Just as it should

6 0

2 years ago