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4 years ago

WHOEVER ANSWERS THIS RIGHT IN 3 MINS GETS BRAINLIEST!!

Mathematics

2 answers:

Zepler [3.9K]4 years ago

8 0

Answer:

brainly.com/question/9842475

Step-by-step explanation:

dsp734 years ago

8 0

Answer: D) reflection across the x-axis

Step-by-step explanation:

Given : The coordinates of a quadrilateral are (1, 2), (4, 2), (1, 4), and (4, 4). After a transformation, the new coordinates are (1, −2), (4, −2), (1, −4), and (4, −4).

Here, the sign of the y-coordinates are changed in the image . [Rest other things remained same.]

Since , it happens in reflection across the x-axis by using rule :

$(x,y)\to (x,-y)$

It means the quadrilateral reflected across the x-axis.

Hence, the transformation occurred : reflection across the x-axis

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Find c for me please

UNO [17]

Answer:

180

Step-by-step explanation:

30+60+90

90+90

180

we have add all the angle

6 0

3 years ago

Help please.

maria [59]

A1=-15
a2=a1+d→-4=-15+d→d=11

8 0

3 years ago

Help!! help!! help!! help!! help!! help!! help!! help!! help!!

oksian1 [2.3K]

Answer:

(8.21, -20.79)

Step-by-step explanation:

Given the simultaneous equation;

$\frac{a}{b} - \frac{b}{2} = 10\\a - b = 29$

From 2;

a = 29 + b ....3

Substitute 3 into 1;

$\frac{29+b}{b} - \frac{b}{2} = 10\\\frac{2(29+b)-b^2}{2b} = 10\\\frac{58+2b-b^2}{2b} = 10\\58+2b-b^2 = 20b\\b^2-2b-58 = -20b\\b^2-2b+20b -58 = 0\\b^2+18b-58 = 0\\$

Factorize

b = -18±√18²-4(-58)/2

b = -18±√324+232/2

b = -18±√556/2

b = -18±23.58/2

b = -18-23.58/2 and -18+23.58/2

b = -41.58/2 and 5.58/2

b = -20.79 and 2.79

Since a = 29 + b

when b = -20.79

a = 29 - 20.79

a = 8.21

Hence the solution to the system of equation is (8.21, -20.79)

7 0

3 years ago

Place the following objects in order from greatest to least gravitational force. Explain your answer.

kozerog [31]

well when thinking of gravity you have to think of the size and mass of the object so,

The sun (largest and most mass)

Earth

Earth's moon

Discover satellite (cause it's tiny and light compared to the sun!)

7 0

3 years ago

In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the function with its graph

MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

$f(x)=(x-2)^{2}+1$

45)

The function g(x) is given by:

$g(x)=f(x-1)$

using f(x) we can find f(x-1)

$g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1$

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

$g(x)'=2(x-3)$

$2(x-3)=0$

$x=3$

Puting it on g(x) we will get y value.

$y=g(3)=(3-3)^{2}+1$

$y=g(3)=1$

Then, the minimum point of this function is (3,1) and it corresponds to (A)

46)

Let's use the same method here.

$g(x)=f(x+2)$

$g(x)=((x+2)-2)^{2}+1$

$g(x)=(x)^{2}+1$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2x$

$0=2x$

$x=0$

Evaluatinf g(x) at this value of x we have:

$g(0)=(x)^{2}+1$

$g(0)=1$

Then, the minimum point of this function is (0,1) and it corresponds to (C)

47)

Let's use the same method here.

$g(x)=f(x)+2$

$g(x)=(x-2)^{2}+1+2$

$g(x)=(x-2)^{2}+3$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}+3$

$g(2)=3$

Then, the minimum point of this function is (2,3) and it corresponds to (B)

48)

Let's use the same method here.

$g(x)=f(x)-3$

$g(x)=(x-2)^{2}+1-3$

$g(x)=(x-2)^{2}-2$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}-2$

$g(2)=-2$

Then, the minimum point of this function is (2,-2) and it corresponds to (D)

I hope it helps you!

8 0

3 years ago