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3 years ago

5

One way to decrease the weight of an object is to?

1 answer:

Lunna [17]3 years ago

8 0

2 ways:

If you increased the speed of rotation of the Earth you would get a perceived decrease in the weight of the object due to an increased centrifugal force.

<span>Increase it fast enough and the momentum of the object will eventually
overcome the gravitational pull on it and it will fly off the planet.</span>

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What are some ways to defend a castle against attack?

ella [17]

Answer:

you can build a mote around your castle and put crocodiles in it.

Explanation:

they will have to go in the water to get to your castle and will get eaten.

4 0

3 years ago

Read 2 more answers

If Abdul pedals his 20 kg bike with a force of 100 N, what will the bike’s acceleration be? The formulas above may be helpful in

Scorpion4ik [409]

Answer:

5 m/s/s

Explanation:

F = ma

100 = 20a

100/20 = a

a = 5 m/s/s

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3 years ago

A student pulls a cart across the floor with a force of 45 N. If the cart travels 10 m, how much work does the cart do on the st

bixtya [17]

I'm assuming we're applying the standard Integral form of the calculation of work. The solution is provided in the image.

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4 years ago

A simple pendulum is made by tying a 2.44 kg stone to a string 4.57 m long. The stone is projected perpendicularly to the string

alexdok [17]

Answer:

$v_{max}=8.2226m/s$

Explanation:

The problem is solved using the law of conservation of energy,

So

$mgL(1-cos\theta)+\frac{1}{2}mv^2_0=\frac{1}{2}mv^2_{max}$

$v_{max}=\sqrt{2gL(1-cos\theta)+v^2_0}$

$v_{max}=\sqrt{2(9.8)(4.57)(1-cos(69.4))+8^2}$

$v_{max}=8.2226m/s$

8 0

3 years ago

Packages having a mass of 6 kgkg slide down a smooth chute and land horizontally with a speed of 3 m/sm/s on the surface of a co

nalin [4]

Answer:

t = 1.02 s

Explanation:

The computation of the time required is shown below:

The package speed for belt is

= 3 - 1

= 2 m/s

Moreover, the decelerative force would be acted on the block i.e u.m.g

So, the decelerative produced

= 0.2 × 9.81

= 1.962 m/s^2

And, final velocity = 0

v = u - at

here

V = 0 = final velocity

u = 2 m/s

so,

0 = 2 - 1.962 × t

t = 1.02 s

5 0

3 years ago