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3 years ago

What is the difference between absolute units of force and gravitational force?

2 answers:

5 0

In absolute system force is normalized as one unit mass times one unit length per second².i.e.

1N=1Kg*1m/1sec². 

But in gravitational system it depends on acceleration due to gravity 'g'. 

This is how it differs from absolute system;because g is not absolute,it is variable. 

Since weight is a force hence its units are different in both system. 

However W is defined as 

W=m.g in both the systems

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Digiron [165]3 years ago

3 0

Although the forces possess the same units, Newton (kg m/s²), the forces are gravitational force is very different due to the fact that it has a predetermined value of acceleration, 9.81 m/s². This value is also subject to change based on the strength of the gravitational field.
Thus, even though the units are the same, their values are different.

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Motor oil, with a viscosity of 0.25 N ∙ s/m2, is flowing through a tube that has a radius of 3.0 mm and is 1.0 m long. The drop

Alex73 [517]

Answer:

The average speed of the oil is 1 m/s.

Explanation:

Given that,

Viscosity $\eta= 0.25 N-s/m^2$

Radius r = 3.0 mm

Length = 1.0 m

Pressure = 200 kPa

We need to calculate the average speed of the oil

Using formula of pressure

$\Delta P=\dfrac{8\pi\eta\rho v}{A}$

$v=\dfrac{A\times\Delta P}{8\pi\eta\rho}$

Where, A = area

$\rho$ = density of oil

$\eta$ = viscosity

Put the value into the formula

$v=\dfrac{\pi\times(3.0\times10^{-3})^2\times200\times10^{3}}{8\pi\times0.25\times0.9}$

$v=1\ m/s$

Hence, The average speed of the oil is 1 m/s.

6 0

4 years ago

A series RL circuit includes a 6.05 V 6.05 V battery, a resistance of R = 0.655 Ω , R=0.655 Ω, and an inductance of L = 2.55 H.

Ivenika [448]

Answer:

The induced emf 1.43 s after the circuit is closed is 4.19 V

Explanation:

The current equation in LR circuit is :

$I=\frac{V}{R} (1-e^{\frac{-Rt}{L} })$ .....(1)

Here I is current, V is source voltage, R is resistance, L is inductance and t is time.

The induced emf is determine by the equation :

$V_{e}=L\frac{dI}{dt}$

Differentiating equation (1) with respect to time and put in above equation.

$V_{e}= L\times\frac{V}{R}\times\frac{R}{L}e^{\frac{-Rt}{L} }$

$V_{e}=Ve^{\frac{-Rt}{L} }$

Substitute 6.05 volts for V, 0.655 Ω for R, 2.55 H for L and 1.43 s for t in the above equation.

$V_{e}=6.05e^{\frac{-0.655\times1.43}{2.55} }$

$V_{e}=4.19\ V$

5 0

3 years ago

Help pls! Explain if you think we should continue to use geothermal power in the future

zhuklara [117]

Answer:

Geothermal power can provide consistent electricity throughout the day and year - continuous baseload power and flexible power to support the needs of variable renewable energy resources, such as wind and solar. Sustainable Investment.

Explanation:

THIS IS WHY WE SHOULD USE GEOTHERMAL ENERGY IN FUTURE

YOU CAN MARK ME AS BRAINIEST IF YOU WANT

4 0

3 years ago

How would we be able to detect a large asteroid if it were heading straight for earth?

Stolb23 [73]

Answer: NASA in US using its super powerful telescope checks all the meteorites ,asteroids that may land on Earth. It deflects the asteroids ,meteorites from their respective path using copper ball . But it is not wholly practical as sometimes these meteorites get enter into key hole .

7 0

4 years ago

A truck with a mass of 1650 kg and moving with a speed of 15.0 m/s rear-ends a 779 kg car stopped at an intersection. The collis

ivanzaharov [21]

Answer:

Truck's speed = 5.21 m/s

Car's speed = 20.2 m/s

Explanation:

Given:

Mass of truck = M = 1650 kg

Speed of the truck initially = U = 15 m/s

Mass of the car = m = 779 kg

Initial speed of the car =u = 0

From the momentum conservation, Total initial momentum = Total final momentum.

M V+m U = M V +m v

⇒ (1650)(15) + 779×0 = (1650)V + 779 v

⇒ 24750 = 1650 V+779 v →(1)

Since the collision is elastic, relative velocity of approach = relative velocity of separation. 15 = v - V

⇒ v =V + 15; This is now substituted in the equation(1) above.

24750 = 1650 V + (799) (V+15)

⇒ 24750 = 1650 V + 799 V + 11985

⇒ 2449 V = 12765

⇒ Final velocity of the truck = $\frac{12765}{2449}$ = 5.21 m/s

Final velocity of the car = v = V+15 = 5.21 + 15 = 20.2 m/s

6 0

3 years ago