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2 years ago

At 10 A.M. a 6-foot tall man cast a 4.5- foot shadow. How long a shadow is cast by a 50-foot tree?

Mathematics

1 answer:

leva [86]2 years ago

6 0

The shadow of the tree would be 47.5hope this help byeee

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a train makes a trip at 65 mi/h. A plane traveling 130 mi/h makes the same trip in 3 fewer hours. Write and solve an equation to

Rudik [331]

The formula used for calculating the time is:

t = d / v

where t is time, d is distance and v is velocity

We know that the difference in the two times is 3 hours, therefore:

d / 65 – d / 130 = 3

Calculating for d:

d = 30 / (1/65 – 1/130)

<span>d = 3900 miles</span>

8 0

3 years ago

Which statements about the graph of the function f(x) = 2x2 – x – 6 are true? Check all that apply.

lbvjy [14]

Hello,

1: dom f=R
2: img f =R
3: 2x²-x-6=2(x²-2x/4+1/46)-6-1/8=2(x-1/4)²-49/8
Vertex=(1/4,-49,8)

4: roots are -3/2 and 2
2(x-1/4)²-49/8=1/8[(4x-1)²-49]=1/8*(4x+6)(4x-8)

5:
From the vertex to ∞
[-1/4 , ∞)

7 0

3 years ago

Find the length of the missing side. triangle with an 8 inch side and 12 inch side with a right angle 8.9 in. 104 in. 4 in 14.4

Mamont248 [21]

Given:

In a triangle, length of one side is 8 inches and length of another side is 12 inches, and an angle is a right angle.

To find:

The length of the missing side.

Solution:

In a right angle triangle,

$Hypotenuse^2=Perpendicular^2+Base^2$

Suppose the measures of sides adjacent to the right angle are 8 inches and 12 inches.

Substituting Perpendicular = 8 inches and Base = 12 inches, we get

$Hypotenuse^2=8^2+12^2$

$Hypotenuse^2=64+144$

$Hypotenuse^2=208$

Taking square root on both sides, we get

$Hypotenuse=\sqrt{208}$

$Hypotenuse=14.422205$

$Hypotenuse\approx 14.4$

The length of the missing side is 14.4 inches. Therefore, the correct option is D.

4 0

2 years ago

Value of sin^-1(sin 9pi/7)

mrs_skeptik [129]

Hint: $\bf \begin{array}{llll}
sin^{-1}[sin(whatever)]= whatever\\\\
cos^{-1}[cos(whatever)]= whatever\\\\
tan^{-1}[tan(whatever)]= whatever
\end{array}\\\\
------------------\\\\
\begin{array}{llll}
sin[sin^{-1}(whatever)]= whatever\\\\
cos[cos^{-1}(whatever)]= whatever\\\\
tan[tan^{-1}(whatever)]= whatever
\end{array}$

3 0

2 years ago

What is the answer

Nastasia [14]

Answer:

both

Step-by-step explanation:

neither of those can be an answer. because x is less than or equal to -1

5 0

3 years ago