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Alexxandr [17]
3 years ago
5

I AM GIVING BRAINLIEST! PLEASEEEEE HELP I NEED HELPPP PLEASEEEE How many atoms of nitrogen in 2.0 mol of dinitrogen monoxide, N2

O?(WITH STEPS)
Chemistry
1 answer:
sveta [45]3 years ago
8 0

Answer: 2.409 x 10^24 atoms  of nitrogen

Explanation:

According to Avogadro

1 mole of any substance = 6.023 x10 ^23 atoms or molecules

1 molecules of N2O has 2 Nitrogen  atoms

Number of mol of Nitrogen atom = 2 X number of moles of N2O

= 2 X 2.0 moles

= 4 moles

Number of atomns = number of moles x avogadro number

Number of atomns=   4.0 x 6.023 x 10 ^23= 2.409 x 10^24 atoms of nitrogen

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Lionel places red blood cells in a beaker of pure water, and then he observes their
scZoUnD [109]

Answer:

The red blood cells will burst

Explanation:

When the red blood cells are placed in pure water, they will gain water by osmosis, swell and finally burst due to their weak cell membranes. This process is referred to as hemolysis.

7 0
2 years ago
Refer to attachment please this is one of my study questions and im stuck
Reil [10]
Percentage yield= actual yield/theoretical yield x100
So you would have to do-
15/22 x 100. Hope this helps!!
3 0
2 years ago
A scuba tank contains a mixture of oxygen (O2) and nitrogen (N2) gas. The oxygen has a partial pressure of PO2=5.62MPa. The tota
dmitriy555 [2]

Answer:

21.16 MPa

Explanation:

Partial pressure of oxygen = 5.62 MPa

Total gas pressure = 26.78 MPa

But

Total pressure of the gas= sum of partial pressures of all the constituent gases in the system.

This implies that;

Total pressure of the system = partial pressure of nitrogen + partial pressure of oxygen

Hence partial pressure of nitrogen=

Total pressure of the system - partial pressure of oxygen

Therefore;

Partial pressure of nitrogen= 26.78 - 5.62

Partial pressure of nitrogen = 21.16 MPa

7 0
2 years ago
Read 2 more answers
What state does a maple tree enter during the winter?
Crank
D. dormancy is the correct answer
3 0
3 years ago
Given the following information, what is the concentration of H2O(g) at equilibrium? [H2S](eq) = 0.671 M [O2](eq) = 0.587 M Kc =
MAVERICK [17]

<u>Answer:</u> The equilibrium concentration of water is 0.597 M

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For a general chemical reaction:

aA+bB\rightleftharpoons cC+dD

The expression for K_{eq} is written as:

K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

The concentration of pure solids and pure liquids are taken as 1 in the expression.

For the given chemical reaction:

2H_2S(g)+O_2(g)\rightleftharpoons 2S(s)+2H_2O(g)

The expression of K_c for above equation is:

K_c=\frac{[H_2O]^2}{[H_2S]^2\times [O_2]}

We are given:

[H_2S]_{eq}=0.671M

[O_2]_{eq}=0.587M

K_c=1.35

Putting values in above expression, we get:

1.35=\frac{[H_2O]^2}{(0.671)^2\times 0.587}

[H_2O]=\sqrt{(1.35\times 0.671\times 0.671\times 0.587)}=0.597M

Hence, the equilibrium concentration of water is 0.597 M

8 0
3 years ago
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