Answer:
The score that separates the lower 5% of the class from the rest of the class is 55.6.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:

Find the score that separates the lower 5% of the class from the rest of the class.
This score is the 5th percentile, which is X when Z has a pvalue of 0.05. So it is X when Z = -1.645.


The score that separates the lower 5% of the class from the rest of the class is 55.6.
Sine is positive while cotangent is negative. So this must mean cosine is negative since cos/sin = cot. In other words, cotangent is the ratio of cosine over sine.
Because cosine is negative and sine is positive, this places theta in quadrant 2
This is where x < 0 and y > 0. Recall that on the unit circle, x = cos(theta) and y = sin(theta).
The answer is choice B) quadrant II
The following answer is B because it shows that it has to multiply the x - axis by the slope (5) to make sure that it can be equat to the y - axis.
y = 5x
y =5(16)
y = 80
(x, y) = (16, 80)
The answer is 1090 pounds because 1300, the max weight, minus 210, the baggage, is 1090. Hope this helps!
3rd one. The circle is on 7 and is going to the left.