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ivann1987 [24]
3 years ago
5

One atom of silicon can properly be combined in a compound with

Chemistry
2 answers:
Over [174]3 years ago
7 0

your answer is c. two atoms of oxygen.

LiRa [457]3 years ago
5 0

One atom of silicon is perfectly combined with the \boxed{{\text{two atoms of oxygen}}}  and forms silicon dioxide.

Further explanation:

Law of multiple proportions:

This law states that the molecule is a particle that is made up of two or more element. The elements are always combined in a ratio of fixed whole number.

Silicon has electron configuration \left[{{\text{Ne}}}\right]3{s^2}3{p^2}  so it can form 4 covalent bonds with other atoms.

One atom of silicon is combined with hydrogen in 1:4 ratio and form {\text{Si}}{{\text{H}}_4} . This compound is known as silane. Thus silicon is not able to combine with three hydrogen atoms.

One atom of silicon is combined with calcium as calcium silicate \left({{\text{C}}{{\text{a}}_{\text{2}}}{\text{Si}}{{\text{O}}_{\text{4}}}}\right)   and Calcium silicon \left({{\text{Ca}}{{\text{H}}_{\text{4}}}{\text{Si}}}\right) . Therefore, silicon would not be able to combine with 4 calcium simultaneously.

One atom of silicon is combined with oxygen in 1:2 ratio and form {\text{Si}}{{\text{O}}_2} . This compound is known as silicon dioxide. Thus silicon can combine with two oxygen atoms.

One atom of silicon is combined with chlorine in 1:4 ratio and form {\text{SiC}}{{\text{l}}_4} . This compound is known as silicon tetrachloride. Thus silicon is not able to combine with one chlorine.

Learn more:

1. Calculate the moles of chlorine in 8 moles of carbon tetrachloride: <u>brainly.com/question/3064603 </u>

2. Which law states the direct relationship between volume and absolute temperature at constant pressure? <u>brainly.com/question/1403211 </u>

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Mole concept

Keywords: One atom of silicon, properly combined, three atom of calcium, one atom of chlorine and two atom of oxygen.

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number of moles of NaOH moles reacted = molarity of NaOH x volume
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according to molar ratio of 2:1
2 mol of NaOH reacts with 1 mol of H₂SO₄
therefore 2.497 x 10⁻³ mol of NaOH reacts with - 1/2 x 2.497 x 10⁻³ mol of H₂SO₄
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