The mass of the balloon decreases as the release of hydrogen gas.
<h3>Mass of hydrogen and percent change</h3>
If the balloon had expanded more then the mass of hydrogen gas will increase inside the balloon but the mass of the balloon decreasing because the hydrogen gas escape from the system means from the balloon.
There is less percent change in the mass of the balloon while on the other hand, the concentration of hydrogen gas increases inside the balloon which leads to expansion of balloon so we can conclude that the mass of the balloon decreases as the release of hydrogen gas.
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D is the correct answer. Chemical reaction rates won't always be constant, you can change the rate of a chemical reaction. Factors that affect chemical reaction rates would be temperature, the concentration (pressure) of the reactant, or just the general surface area (crushing a reactant would be an example). Solvent polarity can also decrease the rate of a chemical reaction. Therefore, A, B, and C are true, leaving D as the answer.
Answer:
0.0042 M is the molarity of tartaric acid in this sample of wine.
Explanation:
To calculate the concentration of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is tartaric acid
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
0.0042 M is the molarity of tartaric acid in this sample of wine.
Answer:
The C14 would be found in Glyceraldehyde-3-Phosphate, and the O18 would also be found in the same molecule
Explanation:
Isotopic labeling is a common method for deducing reaction mechanism in chemistry.
In photosynthesis, the oxygen in the found in Glyceraldehyde-3-Phosphate comes from the carbon dioxide, This is also finally found in the glucose produced at the end of the cycle.
The oxygen in water is released into the atmosphere as the oxygen molecule.
Therefore, the C14 would be found in Glyceraldehyde-3-Phosphate, and the O18 would also be found in the same molecule.
Radioactive decay is expressed by the following formula:
N₀ is the initial number of undecayed atoms.
Nt is the number of undecayed atoms remaining after time t
λ is the decay constant.
The relationship between λ and the half life time t1/2 is:
λ =
= 0.693 / 5.27 = 0.1315
Taking natural logs for both sides of the decay expression:
ln Nt = ln N₀ - λ t
ln Nt = ln 199 - (0.1315 x 20)
= 5.293 - 2.63 = 2.66
From which:
Nt = 14.29 g