Question

You have a 25.2 L sample of gas at 1.25 atm and 25.0 degrees Celsius. How many moles are present in this gas. For your answer, please do not include units and provide your answer to three significant figures.

Answer 1

Answer:

• 1.29 mol

Explanation:

This is a direct application of the equation for ideal gases.

• $PV=nRT$

Where:

• P = pressure = 1.25 atm
• V = volume = 25.2 liter
• R = Universal constant of gases = 0.08206 atm-liter/K-mol
• T = absolute temperature = 25.0ºC = 25 + 273.15 K = 298.15 K
• n = number of moles

Solving for n:

• $n=\frac{PV}{RT}$

Substituting:

$n=\frac{1.25atm\times 25.2liter}{0.08206atm-liter/K-mol\times298.15K }\\\\n=1.29mol$