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GalinKa [24]
3 years ago
6

What is released when an excited electron returns to a lower energy state?

Physics
2 answers:
Marysya12 [62]3 years ago
8 0

Answer:

A proton

Explanation:

oee [108]3 years ago
8 0

Answer:

D. Electromagnetic radiation

Explanation:

...

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When an aluminum bar is connected between a hot reservoir at 860 K and a cold reservoir at 348 K, 2.40 kJ of energy is transferr
Natalija [7]

Answer:

a) \Delta S_{in} = 2.791\,\frac{J}{K}, b) \Delta S_{out} = 6.897\,\frac{J}{K}, c) S_{gen} = 4.106\,\frac{J}{K}, d) Due to irreversibilities due to temperature differences.

Explanation:

a) The change in entropy of the hot reservoir is:

\Delta S_{in} = \frac{2400\,J}{860\,K}

\Delta S_{in} = 2.791\,\frac{J}{K}

b) The change in entropy of the cold reservoir is:

\Delta S_{out} = \frac{2400\,J}{348\,K}

\Delta S_{out} = 6.897\,\frac{J}{K}

c) The total change in entropy of the Universe is modelled after the Second Law of Thermodynamics. Let assume that process is steady:

\Delta S_{in} - \Delta S_{out} + S_{gen} = 0

S_{gen} = \Delta S_{out} - \Delta S_{in}

S_{gen} = 6.897\,\frac{J}{K} - 2.791\,\frac{J}{K}

S_{gen} = 4.106\,\frac{J}{K}

d) Since irreversibilities create entropy as process goes by. The main source of irreversibilities is the existence of temperature differences.

6 0
3 years ago
A 0.50-kg toy is attached to the end of a 1.0-m very light string. The toy is whirled in a horizontal circular path on a frictio
Deffense [45]

Answer:

26.5 m/s

Explanation:

The tension in the string provides the centripetal force that keeps the toy in circular motion. So we can write:

T=m\frac{v^2}{r}

where:

T is the tension in the spring

m = 0.50 kg is the mass of the toy

r = 1.0 m is the radius of the circle (the length of the string)

v is the speed of the toy

The maximum tension in the string is

T = 350 N

If we substitute this value into the equation, we find the maximum speed that the mass can have before the string breaks:

v=\sqrt{\frac{Tr}{m}}=\sqrt{\frac{(350)(1.0)}{0.50}}=26.5 m/s

3 0
3 years ago
Find the volume of a rectangular prism that is 8m long, 4m wide, and 300cm high
konstantin123 [22]
  • L=8m
  • B=4m
  • H=300cm=3m

\\ \bull\tt\longmapsto Volume=LBH

\\ \bull\tt\longmapsto Volume=8(4)(3)

\\ \bull\tt\longmapsto Volume=96m^3

6 0
3 years ago
Read 2 more answers
The absolute magnitude of a star________.
serg [7]
<span>The absolute magnitude of a star is how bright it would appear to us
if it were located ten parsecs (about 32.6 light years) from us.  So it's
a way of treating all stars equally ... on a "level playing field" ... and it
describes each star's actual brightness. </span>
8 0
3 years ago
Describe the steps of aerobic cellular respiration and the amount of energy produced by each step.
Setler [38]

Aerobic cellular respiration have 3 parts, this is Glycolysis, Pyruvate Oxidation and Krebs cycle.

<h3>How is the aerobic breathing process?</h3>

Aerobic respiration consists of carrying out the process of degradation of organic molecules, reducing them to molecules with practically no releaseable energy. The products of the initial degradation of the organic molecule are combined with oxygen in the air and transformed into carbon dioxide and water.

In this case, Aerobic cellular respiration have 3 parts:

  • Glycolysis(yeilds 2ATP & 2NADH).
  • Pyruvate Oxidation(yeilds 2NADH).
  • Krebs cycle(yeilds 2GTP,2FADH2 & 6NADH).

So the total =4ATPs (2GTP equivalent to 2ATP) +10NADH (equivalent to 30ATPs) + 2FADH2(4 ATPs) =38 ATPs.

See more about Aerobic cellular respiration at brainly.com/question/22531444

#SPJ4

3 0
2 years ago
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