What is released when an excited electron returns to a lower energy state?
2 answers:
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Answer:
The thrown rock strike 2.42 seconds earlier.
Explanation:
This is an uniformly accelerated motion problem, so in order to find the arrival time we will use the following formula:
So now we have an equation and unkown value.
for the thrown rock
for the dropped rock
solving both equation with the quadratic formula:
we have:
the thrown rock arrives on t=5.4 sec
the dropped rock arrives on t=7.82 sec
so the thrown rock arrives 2.42 seconds earlier (7.82-5.4=2.42)
Answer:
Value of electric field along the axis and equitorial axis and
respectively.
Explanation:
Given :
Distance between charges ,
Magnitude of charges ,
Dipole moment ,
Case A) (x,y) = (12.0 cm, 0 cm) :
Electric field of dipole in its axis ,
Putting all values and
We get ,
Case B) (x,y) = (0 cm, 12.0 cm) :
Electric field of dipole on equitorial axis ,
Putting all values and
We get ,
Hence , this is the required solution.