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3 years ago

What is released when an excited electron returns to a lower energy state?

Physics

2 answers:

Marysya12 [62]3 years ago

8 0

Answer:

A proton

Explanation:

oee [108]3 years ago

8 0

Answer:

D. Electromagnetic radiation

Explanation:

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The earthquake killed about 60 people and was the strongest earthquake to hit

STatiana [176]

This seems like an incomplete question..

3 0

3 years ago

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A small metal ball is suspended from the ceiling by a thread of negligible mass. The ball is then set in motion in a horizontal

Gemiola [76]

Answer:

Time taken, $T=2\pi \sqrt{\dfrac{l\ cos\theta}{g}}$

Explanation:

It is given that, a small metal ball is suspended from the ceiling by a thread of negligible mass. The ball is then set in motion in a horizontal circle so that the thread’s trajectory describes a cone as shown in attached figure.

From the figure,

The sum of forces in y direction is :

$T\ cos\theta-mg=0$

$T=\dfrac{mg}{cos\theta}$

Sum of forces in x direction,

$T\ sin\theta=\dfrac{mv^2}{r}$

$mg\ tan\theta=\dfrac{mv^2}{r}$ .............(1)

Also, $r=l\ sin\theta$

Equation (1) becomes :

$mg\ tan\theta=\dfrac{mv^2}{l\ sin\theta}$

$v=\sqrt{gl\ tan\theta.sin\theta}$ ...............(2)

Let t is the time taken for the ball to rotate once around the axis. It is given by :

$T=\dfrac{2\pi r}{v}$

Put the value of T from equation (2) to the above expression:

$T=\dfrac{2\pi r}{\sqrt{gl\ tan\theta.sin\theta}}$

$T=\dfrac{2\pi l\ sin\theta}{\sqrt{gl\ tan\theta.sin\theta}}$

On solving above equation :

$T=2\pi \sqrt{\dfrac{l\ cos\theta}{g}}$

Hence, this is the required solution.

4 0

3 years ago

A bag of sand has a density of 45 g/cm3 and a mass of 15 kg. How much space does the sand take up?

Aleks [24]

Volume = mass/density

Volume = 15000 g/45 g/cm3 ≈ 333.3 cm<span>3</span>

3 0

3 years ago

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What is the purpose of using a wedge?

valentinak56 [21]

Think of a wedge as something you put in between objects, so it is a separates objects

4 0

3 years ago

An iron vat is 11 m long at room temperature (20°C). How much longer is it when it contains boiling water at 1 atm pressure?

RoseWind [281]

Answer:

The change in length is 0.01056 m.

Explanation:

Given that,

Length = 11 m

Temperature = 20°C

Pressure = 1 atm

Boiling temperature = 100°C

We need to calculate the length

Using formula of change in linear expansion

$\dfrac{\Delta L}{L}=\alpha_{l}\Delta T$

$\Delta L=L\times\alpha_{l}\times(T_{f}-T_{i})$

Put the value into the formula

$\Delta L=11\times12\times10^{-6}\times(100-20)$

$\Delta L=11\times12\times10^{-6}\times80$

$\Delta L=0.01056\ m$

Hence, The change in length is 0.01056 m.

5 0

3 years ago