<h2>Right answer: Doldrums</h2>
These are also called zones of equatorial calm and it is due a climatic phenomenon that is placed near the Earth equator, attributed to the soft winds, that are called calm winds as well; accompanied by systems of abundant rains and heat.
In this area periods of great calm occur when the winds virtually disappear completely, trapping the sailing ships for long periods (days or weeks). This is why the term <em>doldrum</em> became popular as a colloquial expression in the eighteenth century, to refer to "<em>the caprice of the wind that slows down the navigation to sail".
</em>
The zone is located in the place where two trade winds meet, this means the trade winds of the northern hemisphere <u>converge</u> with those of the southern hemisphere, that is why this region is related to the <u>intertropical convergence zone</u>.
Answer:
a
b

Explanation:
From the question we are told that
The pressure of the manometer when there is no gas flow is 
The level of mercury is 
The drop in the mercury level at the visible arm is 
Generally when there is no gas flow the pressure of the manometer is equal to the gauge pressure which is mathematically represented as

Here
is the density of mercury with value 
and
is the difference in the level of gas in arm one and two
So


Generally the height of the mercury at the arm connected to the pipe is mathematically represented as

=> 
Generally from manometry principle we have that
![P_G + \rho * g * d - \rho * g * [h - (h_m + d)] = 0](https://tex.z-dn.net/?f=P_G%20%2B%20%5Crho%20%2A%20g%20%20%2A%20d%20%20%20-%20%20%5Crho%20%2A%20%20g%20%20%2A%20%5Bh%20-%20%28h_m%20%2B%20d%29%5D%20%3D%200)
Here
is the pressure of the gas
![P_G +13.6 *10^{3} * 9.8 * 0.039 - 13.6 *10^{3} * 9.8 * [0.950 - (0.148 + 0.039)] = 0](https://tex.z-dn.net/?f=P_G%20%2B13.6%20%2A10%5E%7B3%7D%20%2A%209.8%20%20%2A%200.039%20%20%20%20-%20%2013.6%20%2A10%5E%7B3%7D%20%20%2A%20%209.8%20%20%2A%20%5B0.950%20-%20%280.148%20%2B%200.039%29%5D%20%3D%200)

converting to psig
Answer:
a) 
b) x = 4.47 cm
c) 
d) x = 1.48 cm
Explanation:
a) The center of mass is equal to:

Where m is the mass of beads and x is the distances, if x₁ = d₁, x₂ = d₂ and x₃ = d₃

b) If
m₁ = 23g
m₂ = 15 g
m₃ = 58 g
d₁ = 1.1 cm
d₂ = 1.9 cm
d₃ = 3.2 cm

c) The center of the mass of the beads realtive to the center of bead is:

d) 
Answer:
Density = mass/volume
Volume of cube = mass/density
630g/8.94 = 70.5cm^3 (3s.f.)
Since it is a cube, its dimensions of Length x breadth x height=volume
Take 70.5 amd cube root it
![\sqrt[3]{70.4697986577)](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B70.4697986577%29)
=4.13 (3s.f)
hence , it would be 4.13 x 4.13 x 4.13 to find the volume
Hence, the answer would be 4.13cm(3s.f.)