the percent yield of the reaction is 100%.
The percent yield is calculated as the experimental yield divided by the theoretical yield x 100%:
% yield = actual yield / theoretical yield * 100%
% yield of a reaction in this case Rate
In this case, the molar mass of NaBr is 102.9 g / mol, as you know:
444 actual yield = 7.08 mol x 102.9 g / mol = 728.532 g
theoretical yield = 7.08 mol x 102.9 g / mol = 728.532 g
, Replaced by the definition of percent yield:
percent yield = 728.532 grams / 728.532 grams * 100%
percent yield = 100%
Finally, the percent yield of the reaction is 100%.
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FeBr3 is iron bromide. Also known as iron bromide. Iron bromide is an ionic compound in which iron is in a +3 oxidation state.
Learn more about % yield here:brainly.com/question/27979178
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2Al+6HCl ->2AlCl3+3H2 .nAl=m/M=13,5/27=0,5(mol) =>nH2=0,5.3/2=0,75(mol)....VH2=n.22,4=0,75.22,4=16,8(lít)...
Option c is correct bcoz neutrons and protons exist inside nucleus whereas electrons revolve around it
hope it helped