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sukhopar [10]
3 years ago
8

A laboratory technician needs to prepare 500 milliliters of a 2 M solution of sodium hydroxide (NaOH) in a flask. The flask has

a volume of exactly 500 milliliters. Which quantity does the laboratory technician need to measure before making the solution?
Chemistry
1 answer:
Aloiza [94]3 years ago
3 0

Answer : The laboratory technician need to measure before making the solution is the mass of the solute.

Explanation :

Given : Molarity of NaOH = 2 M = 2 mole/L

Volume of solution = 500 ml

Molar mass of NaOH = 40 g/mole

For making the solution, we need the mass of NaOH.

Molarity : It is defined as the number of moles of solute present in on liter of solution.

Formula used : M=\frac{w_1\times 1000}{M_1\times V_s}

where,

M = molarity of the NaOH

w_1 = mass of NaOH

M_1 = molar mass of NaOH

V_s = volume of solution

Now put all the given values in this formula, we get the mass of NaOH.

2mole/L=\frac{w_1\times 1000}{(40g/mole)\times (500)L}

w_1=40g

Therefore, the mass of NaOH is 40 gram.

As we know the molarity of solute, volume of solution and molar mass of the solute. Hence, the laboratory technician will need to measure only mass of the solute before making the solution.

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The true molecular formula of the compound is C₂ClF₅

<h3>Determination of the mole of the compound </h3>
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  • Temperature (T) = 24.3˚C = 24.3 + 273 = 297.3 K
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Number of mole (n) =?

The number of mole can be obtained as by using the ideal gas equation as illustrated below:

n = PV / RT

n = (0.978 × 0.428) / (0.0821 × 297.3)

n = 0.017 mole

<h3>How to determine the molar mass </h3>
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Molar mass = mass / mole

Molar mass = 2.650 / 0.017

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<h3>How to determine the empirical formula</h3>
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F = 61.5 / 19 = 3.237

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Cl = 0.648 / 0.648 = 1

F = 3.237 / 0.648 = 5

Thus, the empirical formula of the compound is C₂ClF₅

<h3>How to determine the molecular formula </h3>
  • Molar mass of compound = 155.88 g/mol
  • Empirical formula = C₂ClF₅
  • Molecular formula =?

Molecular formula = empirical × n = molar mass

[C₂ClF₅]ₙ = 118.084

[(12×2) + 35.5 + (19×5)]ₙ = 155.88

154.5n = 155.88

Divide both side by 154.5

n = 155.88 / 154.5

n = 1

Molecular formula = [C₂ClF₅]ₙ

Molecular formula = [C₂ClF₅]1

Molecular formula = C₂ClF₅

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brainly.com/question/24297883

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The given compounds assuming that they dissociate in solutions  will produce the ions listed above.

The cations which are the positively charged ions in the above compounds are made up of metals and radicals.

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