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kvv77 [185]
4 years ago
6

What is the charge of a potassium (K) ion?

Chemistry
2 answers:
maw [93]4 years ago
7 0

Answer:

B, the charge is +1

Explanation:

science

Svetlanka [38]4 years ago
7 0

Answer:

B. +1

Explanation:

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Which term refers to the number of moles of solute per liter of solution?
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molarity

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PLEASE HELPP!
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Answer:

The arguments both for and against allowing genetically altered meats into the United States is explained below in details.

Explanation:

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  • ENVIRONMENTAL RISK.
  • STRONGER CROPS = LESS PESTICIDES.
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8 0
3 years ago
A tanker truck carrying 6.05×103 kg of concentrated sulfuric acid solution tips over and spills its load. The sulfuric acid solu
irinina [24]

Answer:

6,216.684 kilograms of sodium carbonate must be added to neutralize 6.05\times 10^3 kg of sulfuric acid solution.

Explanation:

Mass of sulfuric acid solution = 6.05\times 10^3 kg=6.05\times 10^6 g

1 kg = 10^3 g

Percentage mass of sulfuric acid = 95.0%

Mass of sulfuric acid = \frac{95.0}{100}\times 6.05\times 10^6 g

=5,747,500 g

Moles of sulfuric acid = \frac{5,747,500 g}{98 g/mol}=58,647.96 mol

H_2SO_4+Na_2CO_3\rightarrow Na_2SO_4+CO_2+H_2O

According to reaction , 1 mole of sulfuric acid is neutralized by 1 mole of sodium carbonate.

Then 58,647.96 moles of sulfuric acisd will be neutralized by :

\frac{1}{1}\times 58,647.96 mol=58,647.96 mol of sodium carbonate

Mass of 58,647.96 moles of sodium carbonate :

106 g/mol\times 58,647.96 mol=6,216,683.76 g

6,216,683.76 g = 6,216,683.76 × 0.001 kg = 6,216.684 kg

6,216.684 kilograms of sodium carbonate must be added to neutralize 6.05\times 10^3 kg of sulfuric acid solution.

3 0
4 years ago
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