Answer:
Sipho catches up Jabu at 6:30 pm
Step-by-step explanation:
Jabu left town A to travel to town B at 6:00 a.m. he drove at an average speed of 80km/h.
At 8:30 am, when Sipho leaves, we will have traveled 2.5 hours at 80 km/h, so he will be 80*2.5 = 200 km ahead.
From then, his position will be given by:
![J(t) = 200 + 80t](https://tex.z-dn.net/?f=J%28t%29%20%3D%20200%20%2B%2080t)
Sipho left town A to travel to town B. He drove at an average speed of 100 km/h.
His position will be given by:
![S(t) = 100t](https://tex.z-dn.net/?f=S%28t%29%20%3D%20100t)
At what time will Sipho catch up jabu?
He will catch up in t hours, and t is found when:
![S(t) = J(t)](https://tex.z-dn.net/?f=S%28t%29%20%3D%20J%28t%29)
So
![100t = 200 + 80t](https://tex.z-dn.net/?f=100t%20%3D%20200%20%2B%2080t)
![20t = 200](https://tex.z-dn.net/?f=20t%20%3D%20200)
![t = \frac{200}{20} = 10](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B200%7D%7B20%7D%20%3D%2010)
He will catch up 10 hours after 8:30 am, that is, 6:30 pm.
Sipho catches up Jabu at 6:30 pm