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3 years ago

What is the length of segment FG?

Mathematics

2 answers:

Alenkinab [10]3 years ago

7 0

Answer:

D. 10.49

Step-by-step explanation:

(see attached for reference)

Here we have two right triangles formed by dividing a larger right triangle by the Altitude (height) of the larger right triangle.

In this special case, all 3 triangles (2 small and 1 large) are SIMILAR and hence we can use the ratios of similar triangles to solve this.

In our case, ΔGFE is similar to ΔGHF

hence FG/GE = GH/FG

We are given that GE = 10 and GH = 11, hence

FG/10 = 11/FG

FG² = (10)(11)

FG² = 110

FG = ±√110

FG= 10.49

stich3 [128]3 years ago

3 0

 $the \: answer \: is \: 10.49 \\ please \: see \: the \: attached \: picture \\ for \: full \: solution \\ hope \: it \: helps$ 

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Artyom0805 [142]

x = 112

This is because

4/7x = 64

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3 years ago

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Cylinders A and B are similar. The volume of cylinder A is 20mm3. Calculate the volume of cylinder B.

MrRa [10]

The question is incomplete. The complete question is :

Cylinders A and B are similar. The length of the cylinder A is 4 mm and the length of cylinder B is 6 mm. The volume of cylinder A is 20mm3. Calculate the volume of cylinder B.

Answer:

67.5 $mm^3$

Step-by-step explanation:

Given that :

Cylinder A and cylinder B are similar.

Let volume of cylinder A = 20 $mm^3$

We know the volume of a cylinder is given by V = $\pi r^2 h$

where, r is the radius of the cylinder

h is the height of the cylinder

We have to find the scale factor.

The length scale factor is = $\frac{6}{4}$

$=\frac{3}{2}$

Area scale factor $=\left(\frac{3}{2}\right)^2$

$=\frac{9}{4}$

∴ Volume scale factor $=\left(\frac{3}{2}\right)^3$

$=\frac{27}{8}$

Therefore, the volume of cylinder B is $=20 \times \frac{27}{8}$

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3 years ago

A group of students are planning a mural at a wall the rectangular wall has dimensions of (6x+7) by (8x+5) and they are planning

zvonat [6]

Answer: $46x^2+73x+15$

Step-by-step explanation:

The area of a rectangle can be calculated with the formula:

$A=lw$

l: the length of the rectangle.

w: the width of the rectangle.

The area of the remaning wall after the mural has been painted, will be the difference of the area of the wall and the area of the mural.

Knowing that the dimensions of the wall are $(6x+7)$ by $(8x+5)$ , its area is:

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As they are planning that the dimensions of the mural be $(x+4)$ by $(2x+5)$ , its area is:

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Then the area of the remaining wall after the mural has been painted is:

$A_{(remaining)}=A_w-A_m\\\\A_{(remaining)}=48x^2+86x+35-(2x^2+13x+20)\\\\A_{(remaining)}=48x^2+86x+35-2x^2-13x-20\\\\A_{(remaining)}=46x^2+73x+15$

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MariettaO [177]

Answer:

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3 years ago