330 would be the 6th term of the sequence
Let the three consecutive odd numbers be x,x+2,x+4.
Given, their sum =219
Therefore, x+x+2+x+4=219
⇒3x+6=219
Subtract 6 from both the sides,
⇒3x+6−6=219−6
⇒3x=213
⇒x=71
The other numbers are x+2=71+2=73 and x+4=71+4=75.
Therefore, threee odd numbers are 71,73 and 75.
Remember PEMDAS
first add -3p^2 and 7p^2 to get 4p^2.
next add 8p^2 and 4p^2 to get 12p^2
12p^2 is your answer
Answer:
Step-by-step explanation:
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