1.65g MgO = 1g Mg
1.65 - 1 = 0.65 g of O in MgO
solve it using proportion:
1g Mg / 0.65g O = x (g) Mg / 16g O
or 1 / 0.65 = x / 16
24.6 g is the answer.
if 1 gram of oxygen requires 1.65 grams of Mg
then 16 grams of oxygen will require 16 ( 1.65) or 26.4 grams.
Answer:
1.15 M
Explanation:
Step 1: Given data
- Initial volume (V₁): 0.125 L
- Initial concentration (C₁): 3.00 M
- Final volume (V₂): 0.325 L
- Final concentration (C₂): ?
Step 2: Calculate the final concentration of the solution
We want to prepare a dilute solution from a concentrated one by adding water. We can calculate the concentration of the dilute solution using the dilution rule.
C₁ × V₁ = C₂ × V₂
C₂ = C₁ × V₁/V₂
C₂ = 3.00 M × 0.125 L/0.325 L = 1.15 M
D. Air molecules touch the warm ground, heating them up
Aqueous nitric acid and aqueous ammonia reacts to form ammonium nitrate
HNO₃(aq)+NH₃(aq) = NH₄NO₃(aq)
HNO₃ +NH3 = NH₄ (+) + NO₃ (-)
Therefore the net ionic equation will be;
H⁺(aq) + NH₃ = NH₄⁺ (aq)
Answer: 2HCO + 4O → H2 + 2CO3
Explanation: Oxomethyl + Oxygen = Dihydrogen + Carbon Trioxide
Reaction Type: SINGLE REPLACEMENT
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