Answer:
The amount of energy released when 50.0 kg is converted into energy is
4.50 x 10A.
A: 18
Answer:
148.2 g of H20
Explanation:
Equation of reaction: 4NH3 + 5O2 ---> 4NO + 6H20
From the equation above, 4 moles of ammonia reacts with 5 moles of oxygen gas to produce 6 moles water.
Molar mass of NH3 = 17 g/mol;
Molar mass of O2= 32 g/mol;
Molar mass of H2O = 18 g/mol
First, we determine the limiting reactant:
4*17 g of NH3 reacts with 5*32 g of O2
Mass Ratio = 68 : 160
Therefore, NH3 is the limiting reactant.
68 g of NH3 reacts to produce 6* 18 g of H20 = 108 g of H2O
93.3 g of NH3 will react to produce (93.3 * 108)/68 g of H20 = 148.2 g of H2O
Therefore, the maximum amount of H2O produced = 148.2 g
Answer:

Explanation:
We have to start this question with <u>Beer's Law</u>,
. On this equation we will have:
<u>A=Absorbance</u>
<u>E=Molar absorption coefficient</u>
<u>b= Optical path</u>
<u>C=Concentration</u>
So, the question is: <u>what values of this equation we know?</u>. If we check the question we have the <u>absorbance value "0.148"</u> additionally we have the slope of the plot, this <u>slope is the molar absorption coefficient</u>, therefore <u>E=0.598 M-1</u>, finally we have also the optical path. <u>The optical path is 1 cm</u> for all devices, so <u>b=1 cm</u>. With all these values we can calculate the concentration "C".



So, we will have a <u>concentration of 0.247 M</u>
I hope it helps!