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maxonik [38]
3 years ago
15

(-5y + 24y4 + 31y? - 30y) = (y – 5)

Mathematics
1 answer:
jek_recluse [69]3 years ago
6 0

Answer:

There are no values of

y

that make the equation true.

No solution

Step-by-step explanation:

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Llana [10]

Answer:

A is the true answer and others are wrong

6 0
2 years ago
ABCD is a rhombus, where m∠AED = 5x – 10. Use the properties of a rhombus to determine the value of x. Question 10 options: A) x
fomenos

Answer:

A) x = 20

Step-by-step explanation:

ABCD is a rhombus, AC and BD are diagonals which intersect each other at point E.

Since, diagonals of a rhombus are perpendicular bisector.

\therefore \: m \angle AED = 90 \degree \\  \therefore \: (5x - 10) \degree = 90 \degree \\ \therefore \: 5x - 10 = 90  \\ \therefore \: 5x  = 90 + 10  \\ \therefore \: 5x  = 100  \\ \\  \therefore \: x  = \frac{100}{5}  \\  \\ \huge \red{ \boxed{ \therefore \: x  =20}}

5 0
3 years ago
A 20­ft ladder is leaning against a house. The bottom of the ladder is 3 ft from the house. To the nearest tenth of a foot, abou
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Answer:  19.8 ft

Step-by-step explanation:

Use the Pythagorean Theorem formula to solve for how high the top of the ladder reach.  

The formula says  a^2 + b^2 = c^2

Where a and b are the two legs and  C is the hypotenuse.

In this situation, the hypotenuse will be length of the ladder , and either  a or b will be the length of the ladder from the building or the length of how long the ladder.

a will be 3 ,  and c will be 20. Input in the values  into the formula and solve for b.

3^2 + b^2 = 20^2

9 + b^2 = 400

-9              -9

 b^2 = 391  

    b = \sqrt{391}

  b  = 19.77371   round to the nearest tenth is ,  19.8

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2 years ago
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3 years ago
Which is equivalent to the following
andrew11 [14]

Answer:

Step-by-step explanation:

(\sqrt[4]{9})^{\frac{1}{2}x}=(9^{\frac{1}{4}})^{\frac{1}{2}x}\\\\=9^{\frac{1}{4}*\frac{1}{2}x}\\\\=9^{\frac{1}{8}x}

5 0
3 years ago
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