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Alenkasestr [34]
4 years ago
9

There is a repulsive force between two charged objects when

Physics
1 answer:
Anton [14]4 years ago
8 0
<h2>Answer: Both objects have charges of the same sign</h2>

When two electrically charged bodies come closer, appears a force that attracts or repels them, depending on the sign of the charges of this two bodies.

This is stated by Coulomb's Law:

"The electrostatic force F_{E} between two point charges q_{1} and q_{2} is proportional to the product of the charges and inversely proportional to the square of the distance d that separates them, and has the direction of the line that joins them"  

Mathematically this law is written as:  

F_{E}= K\frac{q_{1}.q_{2}}{d^{2}}

Where K is a proportionality constant.

Now, if q_{1} and q_{2} have the same sign charge (both positive or both negative), a repulsive force will act on these charges.

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A 12cm candle is placed 6cm from a converging lens with a focal length of 15cm. What is the height of the image of the candle? S
amm1812

Answer:

The height of the image of the candle is 20 cm.

Explanation:

Given that,

Size of the candle, h = 12 cm

Object distance from the candle, u = -6 cm

Focal length of converging lens, f = 15 cm

To find,

The height of the image of the candle.

Solution,

Firstly, we will find the image distance of the candle. Let it is equal to v. Using lens formula to find the image distance.

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

v is image distance

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{15}+\dfrac{1}{(-6)}\\\\v=-10\ cm

If h' is the height of the image. Magnification is given by :

m=\dfrac{h'}{h}=\dfrac{v}{u}

h'=\dfrac{vh}{u}\\\\h'=\dfrac{-10\times 12}{-6}\\\\h'=20\ cm

So, the height of the image of the candle is 20 cm.

3 0
3 years ago
At its closest approach, a moon comes within 200,000 km of the planet it orbits. At that point, the moon is 300,000 km from the
krok68 [10]

Answer:

s₁ = 240,000 km

Explanation:

The distance between both the focuses f₁ and f₂ will be the sum of distances of the moon from each focus at a given point. Therefore,

s = s₁ + s₂

where,

s = total distance between the focuses = ?

s₁ = distance between f1 and moon = 200,000 km

s₂ = distance between f₂ and moon = 300,000 km

Therefore,

s = 200,000 km + 300,000 km

s = 500,000 km

Now, when the distance from f₂ becomes 260,000 km, then the distance from f₁(planet) will become:

s = s₁ + s₂

500,000 km = s₁ + 260,000 km

s₁ = 500,000 km - 260,000 km

<u>s₁ = 240,000 km</u>

5 0
3 years ago
What's the Coulomb's law?
Ulleksa [173]

<span>
In layman's term: </span>like charges don't attract while opposite charges do<span>electrostatic forces between point A( which is charged) and point B (which is also charged) are proportional to the charge of point A and point B. </span><span>there is also something else about this  law that I don't quite remember.</span>

<span>___________________________________________________</span>

<span />Here is the formula:

<span>F = k x Q1 x Q2/d^<span>2</span></span>

<span>What the formula means:</span>

F=force between charges

Q1 and Q2= amount of charge

d=distance between these two charges

k= Coulombs constant (proportionally constant)

________________________________________________

I think that about covers it and hopefully this helped.

4 0
3 years ago
Read 2 more answers
Jake has four pairs of horseshoe magnets in different sizes. He experiments by moving each pair farther and farther apart. Which
Levart [38]

Answer:

a)  the largest pair of magnets

this is the answer

Explanation:

7 0
4 years ago
The last stage of a rocket, which is traveling at a speed of 7700 m/s, consist of two parts that are clamped together: a rocket
svetoff [14.1K]

Answer:

Explanation:

Let the velocity of rocket case and payload after the separation be v₁ and v₂ respectively. v₂ will be greater because payload has less mass so it will be fired with greater speed .

v₂ - v₁ = 910

Applying law of conservation of momentum

( 250 + 100 ) x 7700 = 250 v₁ + 100 v₂

2695000 = 250 v₁ + 100 v₂

2695000 = 250 v₁ + 100 ( 910 +v₁ )

v₁ = 7440 m /s

v₂ = 8350 m /s

Total kinetic energy before firing

= 1/2 ( 250 + 100 ) x 7700²

= 1.037575 x 10¹⁰ J

Total kinetic energy after firing

= 1/2 ( 250 x 7440² + 100 x 8350² )

= 1.0405325 x 10¹⁰ J

The kinetic energy has been increased due to addition of energy generated in firing or explosion which separated the parts or due to release of energy from compressed spring.

3 0
4 years ago
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