We have that Since Cart A spends t=77.5secs and Cart B spends t=50sec
Therefore
The Cart A wins the Race and by 25.5( 77.7-50)secs
From the question we are told
- Two go carts, A and B race each other around a 1.0 km track.
- Go cart A travels at a constant speed of 20.0 m/s.
- Go cart B accelerates uniformly from rest at a rate of 0.333 m/s
For Cart A
Generally the equation for the Velocity is mathematically given as

For Cart B
Generally the Newtons equation for the Motion is mathematically given as

Since
Cart A spends t=77.5secs and Cart B spends t=50sec
Therefore
The Cart A wins the Race and by 25.5( 77.7-50)secs
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Answer:
the object's position.
Explanation: might help ion know
Convection currents in the mantle.
According to newton's 3rd law of motion,
For every action, there is equal and opposite reaction. So if we move a body against a rough surface, there were be reaction against the force applied.
So using conservation of energy, we know:
Work done to move a body = Work done against Friction
So, Force applied * distance moved = coefficient of Friction * Normal Reaction * distance moved
For a body moving against a normal surface, Normal Reaction (R) = mg
or, mass * acceleration * distance (s) = ∪ * R * distance(s)
or, mass * (v^2/2s) = ∪ * mass * gravity
Now, s = stopping distance = v²/ 2∪g
so, using given value,∪=0.05,
s = v2/2*0.05*g
We know, g = 10, so s = v²/(2*0.05*10) = v²
where v = initial velocity
Answer:
0.33 m/s
Explanation:
The graph given is that of distance against time. The slope of such a graph gives the velocity of the object while travelling.
In this graph the change in distance for the last 6 seconds is given by;
The distance is : 10-8 = 2 m
The time in seconds is: 6 s
The velocity = 2/6 = 1/3 m/s
The velocity expressed in decimal form is : 0.33 m/s