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Explanation:
The work done by the shopping basket is 147 J.
<h3>When is work said to be done?</h3>
Work is said to be done whenever a force moves an object through a certain distance.
The amount of work done on the shopping basket can be calculated using the formula below.
Formula:
Where:
- W = Amount of work done by the basket
- m = mass of the shopping basket
- h = height of the shopping basket
- g = acceleration due to gravity.
Form the question,
Given:
- m = 10 kg
- h = 1.5 m
- g = 9.8 m/s²
Substitute these values into equation 2
- W = 10(1.5)(9.8)
- W = 147 J.
Hence, The work done by the shopping basket is 147 J.
Learn more about work done here: brainly.com/question/18762601
The fraction of the kinetic energy of the ball lost during the collision is
.
The given parameters;
- <em>initial speed of the ball, = vi</em>
- <em>final momentum of the ball, Pf = ¹/₃Pi</em>
The initial and final momentum of the ball is calculated as;


The initial and final kinetic energy of the ball is calculated as;

The change in the kinetic energy is calculated as;

Thus, the fraction of the kinetic energy of the ball lost during the collision is
.
Learn more here:brainly.com/question/18566218
The maximum mass of a load that can be lifted by the jack and the distance covered are:
m = 160.2 Kg
h = 25 cm
Given that a certain hydraulic jack is used for lifting load. a force of 250N is applied on a small piston with a diameter of 80cm while the diameter of the larger piston is 2.0m.
The parameters given are
= 250
= Area of the small piston = π
= 22/7 x 
= 0.5 
= ?
= Area of the large piston = π
= π x 1
= 3.14 
To calculate the force on the large piston, we will use the below formula
/
=
/ 
Substitute all the parameters into the equation
250/0.5 =
/3.14
= 1570 N
To calculate the maximum mass of a load that can be lifted by the jack, let us apply Newton second law
F = mg
1570 = 9.8m
m = 1570/9.8
m = 160.2 Kg
.(take g=9.81ms^-2)
If the applied force moves through a distance of 25cm, the distance through which the load is lifted will be
/ 0.25
=
/
h
250/0.125 = 1570/3.14h
make h the subject of the formula
6280h = 1570
h = 1570/6280
h = 0.25 m
Therefore, the distance through which the load is lifted is 25 cm
Learn more here: brainly.com/question/13596980
It’s 2.6 for the average velocity