How does cycling if matter occur in earths mantle

List three ways light can be grouped based on how much light shines through or passes through them

Dovator [93]

Answer:

Materials can be classified based on the amount of light they transmit. Materials, which allow complete transmission of light, are called transparent. Any object can be seen through a transparent material. One example of transparent material is pure glass.

Explanation:

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8 0

3 years ago

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Which type of wires (copper, aluminum, or string) are ferromagnetic metals?

sp2606 [1]

Answer:

Copper isn't ferromagnetic,

Aluminum isn't ferromagnetic,

String has a ferromagnetic property

So in conclusion:

The answer is strings :)

8 0

3 years ago

Can someone solve this problem and explain to me how you got it

Zarrin [17]

1) The electric force changes by a factor of 25

2) The electric force changes by a factor of 16/9

Explanation:

1)

The magnitude of the electrostatic force between two charges is given by Coulomb's law:

$F=k\frac{q_1 q_2}{r^2}$

where:

$k=8.99\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q_1, q_2$ are the two charges

r is the separation between the two charges

In this problem, let's call F the initial force between the two charges when they are at a distance of r.

Later, the distance is changed by a factor of 5. Let's assume it has been increased to a factor of 5: so the new distance is

r' = 5r

Therefore, the new force between the charges is:

$F' = k' \frac{q_1 q_2}{r'^2}=k' \frac{q_1 q_2}{(5r)^2}=\frac{1}{25}(k' \frac{q_1 q_2}{r'^2})=\frac{F}{25}$

So, the force has changed by a factor of 25.

2)

The original force between the two charges is

$F=k\frac{q_1 q_2}{r^2}$

In this problem, we have:

- The distance between the charges is changed by a factor of 6:

r' = 6r

- The charges are both changed by a factor of 8:

$q_1' = 8q_1$

$q_2' = 8q_2$

Substituting into the equation, we find the new force:

$F' = k' \frac{q_1' q_2'}{r'^2}=k' \frac{(8q_1) (8q_2)}{(6r)^2}=\frac{64}{36}(k' \frac{q_1 q_2}{r'^2})=\frac{16}{9}F$

So, the force has changed by a factor of 16/9.

Learn more about electric force:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

6 0

3 years ago

A crate required 900 newtons (N) of force to lift. The crate was lifted by a forklift with an engine that provided 225 N of forc

Alenkinab [10]

The mechanical advantage of the forklift is calculated to be 4.

<h3>MECHANICAL ADVANTAGE:</h3>

The mechanical advantage of a machine can be calculated by dividing the load (F) by effort (F). That is;

M.A = Load/Effort

According to this question, a crate required 900 newtons (N) of force to lift. The crate was lifted by a forklift with an engine that provided 225 N of force. The mechanical advantage is calculated as follows:

M.A = 900N ÷ 225N

M.A = 4.

Therefore, the mechanical advantage of the forklift is calculated to be 4.

Learn more about mechanical advantage at: brainly.com/question/10221970

6 0

3 years ago

a lorry travels 3600m on a test track accelerating constantly at 3m/s squared from standstill. what is the final velocity (3 sig

suter [353]

The final velocity of the truck is found as 146.969 m/s.

Explanation:

As it is stated that the lorry was in standstill position before travelling a distance or covering a distance of 3600 m, the initial velocity is considered as zero. Then, it is stated that the lorry travels with constant acceleration. So we can use the equations of motion to determine the final velocity of the lorry when it reaches 3600 m distance.

Thus, a initial velocity (u) = 0, acceleration a = 3 m/s² and the displacement s is 3600 m. The third equation of motion should be used to determine the final velocity as below.

$2as =v^{2} - u^{2} \\\\v^{2} = 2as + u^{2}$

Then, the final velocity will be

$v^{2} = 2 * 3 * 3600 + 0 = 21600\\ \\v=\sqrt{21600}=146.969 m/s$

Thus, the final velocity of the truck is found as 146.969 m/s.

8 0

3 years ago