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Yanka [14]
4 years ago
15

What will angle r do?

Physics
1 answer:
timama [110]4 years ago
7 0

Answer:

Increase

Explanation:

because it's increasing up.

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Frictional force increases with the increase in the _______________ of the surface.
Sedaia [141]

Answer:

Frictional force increases with the increase in the roughness of the surface.

Explanation:

You will see that the rougher the surface, the greater the wear and tear.

7 0
3 years ago
**HELP ASAP PLEASE!**
Setler79 [48]
They use a spectrograph so the answer would be B.
7 0
3 years ago
Read 2 more answers
A rocket, initially at rest, is fired vertically with an upward acceleration of 10 m/s2. At an altitude of 0.50 km, the engine o
noname [10]

Answer:

The maximum altitude reached with respect to the ground = 0.5 + 0.510 = 1.01 km

Explanation:

Using the equations of motion,

When the rocket is fired from the ground,

u = initial velocity = 0 m/s (since it was initially at rest)

a = 10 m/s²

The engine cuts off at y = 0.5 km = 500 m

The velocity at that point = v

v² = u² + 2ay

v² = 0² + 2(10)(500) = 10000

v = 100 m/s

The velocity at this point is the initial velocity for the next phase of the motion

u = 100 m/s

v = final velocity = 0 m/s (at maximum height, velocity = 0)

y = vertical distance travelled after the engine shuts off beyond 0.5 km = ?

g = acceleration due to gravity = - 9.8 m/s²

v² = u² + 2gy

0 = 100² + 2(-9.8)(y)

- 19.6 y = - 10000

y = 510.2 m = 0.510 km

So, the maximum altitude reached with respect to the ground = 0.5 + 0.510 = 1.01 km

Hope this helps!!!

5 0
3 years ago
1) What is the power in horsepower of a 100 watt light bulb? What is the power in kilowatts of a 200 horsepower engine?
Yuki888 [10]

1).  Use the definition  1 Horsepower = 746 watts

100 watts = (100/746) HP = <em>0.134 Horsepower</em>


2).  Use the definition  Power = (work done) / (time to do the work)

and the definition  Work = (force) x (distance moved)

(3,000 N x 5 m) / second

= (3,000 x 5 N-m) / second

=  (15,000 joules) / second

= 1<em>5,000 watts</em>


3).  Use the definition  Power = (work done) / (time to do the work) , and the definition Work = (force) x (distance moved) , and the 'customary' definition of 1 Horsepower = 550 foot-pounds per second.

Let the answer ... the number of gallons ... be called ' G ' until we know what it actually is.

Weight of water lifted in 1 minute = (G gallons) x (8.34 pounds/gallon)

The distance it's lifted = 30 feet

Work done in 1 minute = (force x distance) = (8.34G x 30) foot-pounds

In just a moment, we're going to need this in seconds:

Power = (8.34G x 30 foot-pounds/minute) x (1 minute / 60 seconds)

Power = (8.34G x 30/60) (foot-pound-minute/minute-sec)

Power = 4.17G foot-pound/sec

The power = 1/2 Horsepower = 225 foot-pounds / sec

So finally, 225 = 4.17G

Divide each side by 4.17, and we have

G = (225/4.17) gallons

<em>G = 53.96 gallons</em>

I really should check this over, but I've had it up to here with gallons, feet, horsepower, and pounds, so I'm not gonna do it.  Read my lips.  It is what it is.  I stand or fall by my answer.  What could go wrong ? !

3 0
3 years ago
Two charges of magnitude 5nC and -2nC are placed at points (2cm,0,0) and
scZoUnD [109]

Answer:

20 cm

Explanation:

Te electric potential enery U = kq₁q₂/r  were q₁ = 5 nC = 5 × 10⁻⁹ C and q₂ = -2 nC = -2 × 10⁻⁹ C and r = √(x - 2)² + (0 - 0)² +(0 - 0)² = x - 2. U =  -0.5 µJ = -0.5 × 10⁻⁶ J, k = 9 × 10⁹ Nm²/C².

So r = kq₁q₂/U

x - 2 = kq₁q₂/U

x = 0.02 + kq₁q₂/U m

x = 0.02 + 9 × 10⁹ Nm²/C² × 5 × 10⁻⁹ C × -2 × 10⁻⁹ C/-0.5 × 10⁻⁶ J

x = 0.02 - 90 × 10⁻⁹ Nm²/-0.5 × 10⁻⁶ J

x = 0.02 + 0.18 = 0.2 m = 20 cm

7 0
3 years ago
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