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3 years ago

Which of the following is most likely to be an observation made by a physiologist

Physics

1 answer:

Naya [18.7K]3 years ago

3 0

Do you have the answer choices ?

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6/10

g100num [7]

Answer:pounds

Explanation:

7 0

2 years ago

Please help me with the equations for this! Three uniform spheres are fixed at the positions shown in the diagram. ( there is a

lora16 [44]

The change in gravitational potential energy due to change in position must be the change in it's kinetic energy as the system is isolated! so find out the potential energies of the two different points!

PE=−[GM1M2]÷R

 Potential energy of a particle due to mass A is not affected by presence of any other mass B !

7 0

3 years ago

If a 2 cm vector represents speed, and 1 cm equals 5 m/s, how fast is the represented

Ne4ueva [31]

Answer: 10m/s

Explanation: Since a single vector with length of 1cm expresses 5m/s, the vector which has a length doubled from the original vector should have the speed which is also doubled.

6 0

3 years ago

A certain parallel-plate capacitor is filled with a dielectric for which κ = 5.0. The area of each plate is 0.027 m2, and the pl

alexdok [17]

Answer:

Energy will be $4.776\times 10^{-5}J$

Explanation:

We have given that dielectric constant k = 5

Area of the plate $A=0.027m^2$

Distance between the plates $d=2mm=2\times 10^{-3}m$

Electric field E = 200 kN/C

We know that capacitance is given by $C=\frac{K\epsilon _0A}{d}=\frac{5\times 8.85\times 10^{-12}\times 0.027}{2\times 10^{-3}}=0.597\times 10^{-9}F$

We know that electric field is given by $E=\frac{V}{d}$

So $V=Ed=200\times 10^3\times 2\times 10^{-3}=400volt$

So energy will be $E=\frac{1}{2}CV^2=\frac{1}{2}\times 0.597\times 10^{-9}\times 400^2=4.776\times 10^{-5}J$

6 0

3 years ago

Two trucks with equal mass are attracted to each other with a gravitational force of 5.3 x 10 -4 N. The trucks are separated by

HACTEHA [7]

Answer:

7327 kg or 7.3 tons

Explanation:

We have Newton formula for attraction force between 2 objects with mass and a distance between them:

$F_G = G\frac{M_1M_2}{R^2}$

where $G =6.67408*10^{-11} m^3/kgs^2$ is the gravitational constant on Earth. $M = M_1 = M_2$ is the masses of the 2 objects. and R = 2.6m is the distance between them.

$F_G = 5.3*10^{-4}N$ is the attraction force.

$5.3*10^{-4} = 6.67408*10^{-11}\frac{M^2}{2.6^2}$

$7941265 = \frac{M^2}{2.6^2}$

$M^2 = 53682948.76$

$M = \sqrt{53682948.76} \approx 7327 kg$ or 7.3 tons

3 0

3 years ago