Um A :)
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Simplify:
−3=12y−5(2y−7)
−3=12y+(−5)(2y)+(−5)(−7)(Distribute)
−3=12y+−10y+35
−3=(12y+−10y)+(35)(Combine Like Terms)
−3=2y+35
Flip the equation.
2y+35=−3
Subtract 35 from both sides.
2y+35−35=−3−35
2y=−38
Divide both sides by 2.
2y/2=−38/2
y=−19
For it to be a solution, it has to satisfy both inequalities...
subbing in (-4,-1)
2x + y < -5 -x + y > 0
2(-4) - 1 < - 5 -(-4) - 1 > 0
-8 - 1 < -5 4 - 1 > 0
-9 < -5.....true 3 > 0....true
solution is (-4,-1)