Answer:
816.33 kg
Explanation:
To solve this problem we'll need to keep in mind the <em>formula for the kinetic energy of an object</em>:
Where E is the kinetic energy, m is the object's mass and v its velocity.
We<u> input the data given by the problem</u>:
- 500000 J = 0.5 * m * (35 m/s)²
And <u>solve for m</u>:
Answer:
Mass= 2.77g
Explanation:
Applying
P=2.09atm, V= 1.13L, R= 0.082, T= 291K, Mm of N2= 28
PV=nRT
NB
Moles(n) = m/M
PV=m/M×RT
m= PVM/RT
Substitute and Simplify
m= (2.09×1.13×28)/(0.082×291)
m= 2.77g
True, Scientific theories may change with the addition of new information or improved experiments and observations.
Answer:
61.6 g of CO₂ were produced
Explanation:
Let's think the combustion
C + O₂ → CO₂
First of all we determine the moles:
16.8 g . 1mol / 12 g = 1.4 moles
As the question states the oxygen is remained unreacted, the oxygen is the reactant in excess, so the limiting is the C.
1 mol of C produces 1 mol of CO₂, so 1.4 moles in the reactant will produce the same amount products.
We convert the moles to mass.
1.4 mol . 44 g / 1mol = 61.6 g
The answer is b! that is how you measure volume. have a good day and stay safe! :)