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Katyanochek1 [597]
3 years ago
14

(1) 10x’y' + 15xy? :

Mathematics
2 answers:
ahrayia [7]3 years ago
4 0

Answer:

factor: 5(2x'y'+3xy)

Step-by-step explanation:

thats for factoring, i didnt know what you needed

Neko [114]3 years ago
4 0

Answer:

25xy

Step-by-step explanation:

collect like terms

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Answer:

yus can you answer this for me

Step-by-step explanation:

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3 years ago
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To get to school you can travel by car, bus or bicycle. If you travel by car, there is a 50% chance you will be late because the
Irina18 [472]

Answer:

a) 16.66%

b) 5%

Step-by-step explanation:

a)

Since the teacher assumes each of the three possibilities are equally likely, then he assumes 33.33% to each one.

In this case the probability that you traveled to school that day by car would be

50%  of 33.33% = (0.5)(0.3333) = 0.1666 = 16.66%

b)

In this case, the teacher would assume

90% ride on bicycle

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10% travel by car

So, in this case the probability would be

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6 0
3 years ago
More work that was due yesterday help?
Troyanec [42]

So what is the question?

8 0
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A rubber ball is dropped onto a hard surface from a height of 9 feet, and it bounces up and down. At each bounce it rises to 80%
8_murik_8 [283]
There are 12 inches in a foot, so 9ft = 108in. Also, 80% = 0.8. Therefore the formula is: h(n) = 108 * 0.8^n. To find the bounce height after 10 bounces, substitute n=10 into the equation: h(n) = 108 * 0.8^10 = 11.60in (2.d.p.). Finally to find how many bounces happen before the height is less than one inch, substitute h(n) = 1, then rearrage with logarithms to solve for the power, x: 108 * 0.8^x = 1; 0.8^x = 1/108; Ln(0.8^x) = ln(1/108); xln(0.8) = ln(1\108); x = ln(1/108) / ln(0.8) = -4.682 / -0.223 = 21 bounces
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3 years ago
Can you help me with part b of problem 25
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C is the correct answer for the problem hope it helps :)
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