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Kaylis [27]
2 years ago
15

What type of function is represented by the table of values below?

Mathematics
2 answers:
ZanzabumX [31]2 years ago
6 0

Answer:

C. linear

Step-by-step explanation:

Linear relationships are functions that form straight lines. The equation for the table is y=4x, which is not only a linear relationship, but also a proportional relationship.

GrogVix [38]2 years ago
3 0

Answer:

C. Linear

Step-by-step explanation:

The function is going up by a constant rate of 4.

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Maria and Franco are mixing sports drinks for a track meet. Maria uses 23 cup of powdered mix for every 2 gallons of water. Fran
Anastaziya [24]

Answer:

Maria

Step-by-step explanation:

Find the ratio of powdered mix to water for each drink.

For Maria:

(2/3 cup) / (2 gallon)

= 1/3 cup per gallon

For Franco:

(1 1/4 cup) / (5 gallon)

= (5/4 cup) / (5 gallon)

= 1/4 cup per gallon

Since 1/3 is bigger than 1/4, Maria's sports drink is stronger.

4 0
2 years ago
What is 6 divide by 5
lara31 [8.8K]
Hey there!

6 divided by 5 = 1.2


Hope this helps!
Have a great day! (:
7 0
3 years ago
Evaluate the line integral by the two following methods. xy dx + x2 dy C is counterclockwise around the rectangle with vertices
Airida [17]

Answer:

25/2

Step-by-step explanation:

Recall that for a parametrized differentiable curve C = (x(t), y(t)) with the parameter t varying on some interval [a, b]

\large \displaystyle\int_{C}[P(x,y)dx+Q(x,y)dy]=\displaystyle\int_{a}^{b}[P(x(t),y(t))x'(t)+Q(x(t),y(t))y'(t)]dt

Where P, Q are scalar functions

We want to compute

\large \displaystyle\int_{C}P(x,y)dx+Q(x,y)dy=\displaystyle\int_{C}xydx+x^2dy

Where C is the rectangle with vertices (0, 0), (5, 0), (5, 1), (0, 1) going counterclockwise.

a) Directly

Let us break down C into 4 paths \large C_1,C_2,C_3,C_4 which represents the sides of the rectangle.

\large C_1 is the line segment from (0,0) to (5,0)

\large C_2 is the line segment from (5,0) to (5,1)

\large C_3 is the line segment from (5,1) to (0,1)

\large C_4 is the line segment from (0,1) to (0,0)

Then

\large \displaystyle\int_{C}=\displaystyle\int_{C_1}+\displaystyle\int_{C_2}+\displaystyle\int_{C_3}+\displaystyle\int_{C_4}

Given 2 points P, Q we can always parametrize the line segment from P to Q with

r(t) = tQ + (1-t)P for 0≤ t≤ 1

Let us compute the first integral. We parametrize \large C_1 as

r(t) = t(5,0)+(1-t)(0,0) = (5t, 0) for 0≤ t≤ 1 and

r'(t) = (5,0) so

\large \displaystyle\int_{C_1}xydx+x^2dy=0

 Now the second integral. We parametrize \large C_2 as

r(t) = t(5,1)+(1-t)(5,0) = (5 , t) for 0≤ t≤ 1 and

r'(t) = (0,1) so

\large \displaystyle\int_{C_2}xydx+x^2dy=\displaystyle\int_{0}^{1}25dt=25

The third integral. We parametrize \large C_3 as

r(t) = t(0,1)+(1-t)(5,1) = (5-5t, 1) for 0≤ t≤ 1 and

r'(t) = (-5,0) so

\large \displaystyle\int_{C_3}xydx+x^2dy=\displaystyle\int_{0}^{1}(5-5t)(-5)dt=-25\displaystyle\int_{0}^{1}dt+25\displaystyle\int_{0}^{1}tdt=\\\\=-25+25/2=-25/2

The fourth integral. We parametrize \large C_4 as

r(t) = t(0,0)+(1-t)(0,1) = (0, 1-t) for 0≤ t≤ 1 and

r'(t) = (0,-1) so

\large \displaystyle\int_{C_4}xydx+x^2dy=0

So

\large \displaystyle\int_{C}xydx+x^2dy=25-25/2=25/2

Now, let us compute the value using Green's theorem.

According with this theorem

\large \displaystyle\int_{C}Pdx+Qdy=\displaystyle\iint_{A}(\displaystyle\frac{\partial Q}{\partial x}-\displaystyle\frac{\partial P}{\partial y})dydx

where A is the interior of the rectangle.

so A={(x,y) |  0≤ x≤ 5,  0≤ y≤ 1}

We have

\large \displaystyle\frac{\partial Q}{\partial x}=2x\\\\\displaystyle\frac{\partial P}{\partial y}=x

so

\large \displaystyle\iint_{A}(\displaystyle\frac{\partial Q}{\partial x}-\displaystyle\frac{\partial P}{\partial y})dydx=\displaystyle\int_{0}^{5}\displaystyle\int_{0}^{1}xdydx=\displaystyle\int_{0}^{5}xdx\displaystyle\int_{0}^{1}dy=25/2

3 0
3 years ago
a recipe for making 4 cups of soup requires 3 cups of water at this rate how many cups of water are required to make 24 cups of
Tema [17]

Answer:

18

Step-by-step explanation:

4 divided by 24 is 6

6x3=18

8 0
3 years ago
Answer choices:
vova2212 [387]
A and T are points. On their own, they cannot define a line. So we can rule out choice A

WCR and TRA are angles. For any triple the points do not fall on the same straight line. So we cannot define any lines here. This crosses off choice B

Choice C is the answer because WC does define a line. We only need two points to form a line. Similarly CR does the same job. We draw a line marker with two arrows at each end to be placed over the letters to indicate "line". 

Choice D is similar to choice D; however, it is not the answer because WT is the same line as WC. In other words, WC = WT. We haven't named a new line at all. We're simply repeating ourselves. 
6 0
3 years ago
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