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romanna [79]
3 years ago
13

In ΔDEF, e = 2.7 inches, ∠F=49° and ∠D=58°. Find the length of f, to the nearest 10th of an inch.

Mathematics
1 answer:
Anton [14]3 years ago
7 0

Answer:2.1

Step-by-step explanation:

\text{Draw a diagram:}

Draw a diagram:

D

E

F

e = 2.7

f = ?

49°

58°

\text{A.S.A.}\rightarrow \text{Law of Sines}

A.S.A.→Law of Sines

\frac{a}{\sin A}=\frac{b}{\sin B}

sinA

a

​

=

sinB

b

​

\text{Find other angle:}

Find other angle:

\angle E=180-49-58=73^{\circ}

∠E=180−49−58=73

∘

D

E

F

e = 2.7

f = ?

49°

58°

73°

\frac{f}{\sin 49}=\frac{2.7}{\sin 73}

sin49

f

​

=

sin73

2.7

​

f=\frac{2.7\sin 49}{\sin 73} \approx 2.131 \approx 2.1

f=

sin73

2.7sin49

​

≈2.131≈2.1

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If the first step in the solution of the equation 2x - 8 = 5x + 3 is "subtract 2x," then in the form of a paragraph, explain in
monitta

x = \frac{-11}{3}

<u>Step-by-step explanation:</u>

Here we have , If the first step in the solution of the equation 2x - 8 = 5x + 3 is "subtract 2x," then in the form of a paragraph, explain in complete sentences the next steps necessary to completely solve the equation for x. Let's solve this :

2x - 8 = 5x + 3

⇒ 2x - 8 = 5x + 3

⇒ (2x - 8)-2x = (5x + 3)-2x { subtract 2x from both side }

⇒ 0 - 8 = 5x-2x + 3

⇒ - 8 = 3x + 3

⇒ - 8 -3= 3x + 3-3 { subtract 3 from both sides }

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3 0
3 years ago
Martin throws a ball straight up in the air. the equation h(t) = -16t^2 + 40t + 5 gives the height of the ball, in feet, t secon
Lisa [10]

Answer:

2.62 seconds

Step-by-step explanation:

Let

t ----> the time in seconds

h(t) ----> he height of the ball, in feet

we have

h(t)=-16t^2+40t+5

we know that

When the ball hits the ground, the height is equal to zero

so

-16t^2+40t+5=0

The formula to solve a quadratic equation of the form

at^{2} +bt+c=0

is equal to

t=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^2+40t+5=0

so

a=-16\\b=40\\c=5

substitute in the formula

t=\frac{-40\pm\sqrt{40^{2}-4(-16)(5)}} {2(-16)}

t=\frac{-40\pm\sqrt{1,920}} {-32}

t=\frac{-40+\sqrt{1,920}} {-32}=-0.12\ sec

t=\frac{-40-\sqrt{1,920}} {-32}=2.62\ sec

therefore

The solution  is t=2.62 seconds

4 0
3 years ago
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