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r-ruslan [8.4K]
2 years ago
11

Which statement concerning elements is true?

Chemistry
1 answer:
Marina86 [1]2 years ago
7 0
The answer is either number one or two.
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___________ reactions form predominately or exclusively one enantiomer. ____________ is the addition of a single oxygen atom to
ArbitrLikvidat [17]

1) <u>Stereo-selective (or enantioselective)</u> reactions form predominately or exclusively one enantiomer.

2) Epoxidation is the addition of a single oxygen atom to an alkene to form an epoxide.

3) <u>Hydrogenation (or reduction)</u> of an alkene forms an alkane by addition of H₂.

4) <u>Dihydroxylation</u> is the addition of two hydroxy groups to a double forming, a 1,2-diol or glycol.

5) <u>oxidative</u> cleavage of an alkene breaks both the σ and π bonds of the double bond to form two carbonyl groups.

6)  <u>Regioselective</u> reactions form predominately or exclusively one constitutional isomer.

7)  <u>Syn</u> dihydroxylation results when an alkene is treated KMnO4 or OsO4, where each reagent adds two oxygen atoms to the same side of the double bond.

7 0
3 years ago
A helium filled ballon had a volume of 8.50 L on the ground at 20.0 C and a pressure of 750.0 Torr. After the ballon was release
Marrrta [24]

Answer:

V_2=12.1L

Explanation:

Hello!

In this case, according to the given data of volume, pressure and temperature, it is possible to infer this problem can be solved via the combined gas law:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

Thus, regarding the question, we evidence we need V2, but first we make sure the temperatures are in Kelvins:

T_1=20+273=293K\\\\T_2=-40+273=233K

Then, we obtain:

V_2=\frac{P_1V_1T_2}{T_1P_2}\\\\V_2=\frac{0.987atm*8.50L*233K}{293K*0.550atm}\\\\V_2=12.1L

Best regards!

5 0
2 years ago
What is the total number of calories of heat energy absorbed when 10 grams of water is vaporized at its normal boiling point
Darya [45]

<u>Answer:</u> The amount of energy absorbed by water is 5390 Calories

<u>Explanation:</u>

To calculate the amount of heat absorbed at normal boiling point, we use the equation:

q=m\times L_{vap}

where,

q = amount of heat absorbed = ?

m = mass of water = 10 grams

L_{vap} = latent heat of vaporization = 539 Cal/g

Putting values in above equation, we get:

q=10g\times 539Cal/g=5390Cal

Hence, the amount of energy absorbed by water is 5390 Calories

6 0
3 years ago
Is this True or false?
kherson [118]

Answer:

true

Explanation:

7 0
3 years ago
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Is the chemical equation balanced?<br><br> Yes or no
Strike441 [17]
I think it is not so no
6 0
2 years ago
Read 2 more answers
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