Question

1,3,9,27 what are the next 5 numbers? and what is the nth term please show working out

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

81, 243, 729, 2187, 6561

Step-by-step explanation:

Note that the

third term 9 = 3²

fourth term 27 = 3³

Thus to obtain a particular term in the sequence we require the exponent to be one less than the terms position n in the sequence, that is

$a_{n}$ = $3^{n-1}$ , thus

first term 1 → $3^{1-1}$ = $3^{0}$ = 1

The next 5 terms in the sequence are

$a_{5}$ = $3^{5-1}$ = $3^{4}$ = 81

$a_{6}$ = $3^{6-1}$ = $3^{5}$ = 243

$a_{7}$ = $3^{7-1}$ = $3^{6}$ = 729

$a_{8}$ = $3^{8-1}$ = $3^{7}$ = 2187

$a_{9}$ = $3^{9-1}$ = $3^{8}$ = 6561