The veretx is normally the minimum value
hack:
for f(x)=ax²+bx+c
the x value of the vertex is -b/2a
so
f(x)=1x²-16x+71
x value is -(-16)/(2*1)=16/2=8
find f(8) to find y value of vertex
f(8)=8²-16(8)+71
f(8)=64-128+71
f(8)=7
the vertex is (8,7)
the minimum value is 7
We are give the equation of the perimeter of the triangle as follows:
2a + b = 15.7
where b represents the base.
Now, if we want to calculate the length of the base, all we have to do is isolate the b in one side of the equation as follows:
b = 15.7 - 2a
We know that a = 6.3 cm, therefore, the length of the base can be calculated as follows:
b = 15.7 - 2(6.3) = 3.1 cm
Answer:
(x, y) --> (x + 14, y + 8)
Step-by-step explanation:
Look at 1 original point and its corresponding translated point.
Let's look at F and F'.
To go from F to F', you need to go right in x 14 units.
Then you need to go up in y 8 units.
The translation rule is to add 14 to x and 8 to y.
(x, y) --> (x + 14, y + 8)