Answer:
The second alternative is correct
Step-by-step explanation:
We have been given the expression;

The above expression can be re-written as;

On the other hand;
![y^{\frac{1}{3}}=\sqrt[3]{y}](https://tex.z-dn.net/?f=y%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7By%7D)
Therefore, we have;
![x^{9}\sqrt[3]{y}](https://tex.z-dn.net/?f=x%5E%7B9%7D%5Csqrt%5B3%5D%7By%7D)
<em>The answer is
</em>The reason we get this answer is because when you are converting from exponential form, to radical form you always place the numerator as our constant's exponent in the radical <em>(

is called the radicand because it is located in the radical)</em> and the denominator in front of the radical, where it would be called the index.
<em>Here's what a formula would look like:</em> ![( \sqrt[n]{x} ) ^{q}=x^{ \frac{p}{q} }](https://tex.z-dn.net/?f=%28%20%5Csqrt%5Bn%5D%7Bx%7D%20%29%20%5E%7Bq%7D%3Dx%5E%7B%20%5Cfrac%7Bp%7D%7Bq%7D%20%7D%20)
Thank you for your question! I hope this helped! Have an amazing day and feel free to let me know if I can help you further! :D
<span>4x – 20 = 900
4x = 900+20
4x = 920
x = 920/4
x = 230
he earned $230
</span>
Answer:
x=4 y=0
Step-by-step explanation:
You add the two equations together to get 3x=12. You derive x=4 and y=0 from that.