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irga5000 [103]
3 years ago
11

Emma was given a system of equations to solve by graphing. Which statement correctly identifies Emma’s error?

Mathematics
1 answer:
Alexxandr [17]3 years ago
8 0

Answer:

line one should have a y-intercept at (0,2).

Step-by-step explanation:

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Sam makes about 79% of his free throws. he shoots 60 free throws. about how manywill he make?
nataly862011 [7]
Hey You!

60 * 79% = 47.4

You can solve it by:

(60 ÷ 100 × 79 = 47.4)

Sam will make 47.4 of his throws.
5 0
3 years ago
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Express 72×12 in the exponential form​
kobusy [5.1K]
72*12 = 2*2*2*2*2*3*3*3 = 2^5*3^3
3 0
4 years ago
I will give brainiest to whoever answers correctly !!
Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

a) The interest generated over the 9 months is how much the woman paid for use of the money, then:

I=C.t.i\\C=3000\\t=9\\i=3.5%=0.035\\I=3000.9.0.035=945\\I=945

Therefore , the woman paid $945 for the use of the money.

b) The total amount that she repaid the bank is:

C_{t} =C+I=3000+945=3945\\C_{t} =3945

Finally we have that the woman paid $3945 to the bank

PLEASE MARK ME AS BRAINLIEST

7 0
3 years ago
A sample of 125 pieces of yarn had mean breaking strength 6.1 N and standard deviation 0.7 N. A new batch of yarn was made, usin
AlexFokin [52]

Answer:

The 90% confidence interval for the difference in mean breaking strength between the two types of yarn is (0.08N, 0.52N).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction of normal variables:

When we subtract two normal variables, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

A sample of 125 pieces of yarn had mean breaking strength 6.1 N and standard deviation 0.7 N.

This means that \mu_1 = 6.1, s_1 = \frac{0.7}{\sqrt{125}} = 0.0626

In a sample of 75 pieces of yarn from the new batch, the mean breaking strength was 5.8 N and the standard deviation was 1.0 N.

This means that \mu_2 = 5.8, s_2 = \frac{1}{\sqrt{75}} = 0.1155

Distribution of the difference:

\mu = \mu_1 - \mu_2 = 6.1 - 5.8 = 0.3

s = \sqrt{s_1^2+s_2^2} = \sqrt{0.0626^2+0.1155^2} = 0.1314

Confidence interval:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.645.

Now, find the margin of error M as such

M = zs

M = 1.645*0.1314 = 0.22

The lower end of the interval is the sample mean subtracted by M. So it is 0.3 - 0.22 = 0.08N

The upper end of the interval is the sample mean added to M. So it is 0.3 + 0.22 = 0.52N

The 90% confidence interval for the difference in mean breaking strength between the two types of yarn is (0.08N, 0.52N).

3 0
3 years ago
if 1/2 a lemon will make1/3 of a gallon of lemonade, how many lemons will it take to make a full gallon of lemonade?
AnnyKZ [126]
1/2 = 1/3g
x = 1g
1/2*3 = x
Therefore, it will take 3/2 or 1.5 or 1 1/2 lemons.
5 0
3 years ago
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