Answer:
B. 4.05 liters
Step-by-step explanation:
Answer:
L(18, 20)
Step-by-step explanation:
In JL, K is the midpoint. The coordinates of J are (2, 2), and the
coordinates of K are (10, 11). What are the coordinates of L?
Solution:
If O(x, y) is the midpoint between two points A(
) and B(
). The equation to determine the location of O is given by:
![x=\frac{x_1+x_2}{2} \\\\y=\frac{y_1+y_2}{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7Bx_1%2Bx_2%7D%7B2%7D%20%5C%5C%5C%5Cy%3D%5Cfrac%7By_1%2By_2%7D%7B2%7D)
Since JL is a line segment and K is the midpoint. Given the location of J as (2, 2) and K as (10, 11). Let (
) be the coordinate of L. Therefore:
![10=\frac{2+x_2}{2} \\\\20=2+x_2\\\\x_2=18](https://tex.z-dn.net/?f=10%3D%5Cfrac%7B2%2Bx_2%7D%7B2%7D%20%5C%5C%5C%5C20%3D2%2Bx_2%5C%5C%5C%5Cx_2%3D18)
![11=\frac{2+y_2}{2} \\\\22=2+y_2\\\\y_2=20](https://tex.z-dn.net/?f=11%3D%5Cfrac%7B2%2By_2%7D%7B2%7D%20%5C%5C%5C%5C22%3D2%2By_2%5C%5C%5C%5Cy_2%3D20)
Therefore L = (18, 20)
Answer:
q = 15
Step-by-step explanation:
Given
f(x) = x² + px + q , then
f(3) = 3² + 3p + q = 6 , that is
9 + 3p + q = 6 ( subtract 9 from both sides )
3p + q = - 3 → (1)
---------------------------------------
f'(x) = 2x + p , then
f'(3) = 2(3) + p = 0, that is
6 + p = 0 ( subtract 6 from both sides )
p = - 6
Substitute p = - 6 into (1)
3(- 6) + q = - 3
- 18 + q = - 3 ( add 18 to both sides )
q = 15
Answer:
in steps
Step-by-step explanation:
DE // BC
m∠ADE = m∠ABC and m∠AED = m∠ACB
∴ ΔADE similar to ΔABC
AB/AD = AC/AE
(AD + DB) / AD = (AE + EC) / AE
AD/AD + DB/AD = AE/AE + EC/AE
1 + DB/AD = 1 + EC/AE
DB/AD = EC/AE (AD/DB = AE/EC)