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3 years ago

What mixture can be separated by using a filter?

Chemistry

1 answer:

nexus9112 [7]3 years ago

4 0

<h2>Answer: </h2>

Option 2nd - a mixture of solid particles in a liquid.

<h2>Explanation: </h2>

For a Mixture of two immiscible liquids (for example water and oil) it is not possible to filter them with a filter as both of the liquid will pass through it.
For a mixture of a solid and a liquid (for example sand and water) it can be easily separated through a filter as on filtration solid will be left on the filter and the liquid will pass through it.
For a mixture of two miscible liquids (for example milk and water) both of them will form a single identity, and on filtration both of them will pass through the filter. Hence it is not possible to separate them through filter.
For a mixture of liquid and gas (for example drinking soda or Pepsi) filter is not needed for their separation as it will be separated when exposed in air.

Result: Option 2 is the correct answer.

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Which of the following matches is not correct?

Furkat [3]

Answer:

SO42 - Trigonal planar ion

Explanation:

The SO4^2- ion is tetrahedral and not trigonal planar because the sulphur atom has four regions of electron density which includes the lone pair of electrons on sulphur atom.

This accounts for the observed tetrahedral arrangement of electron pairs around the central sulphur atom in SO4^2- ion, hence the answer.

8 0

3 years ago

A 845 mL NaCl solution is diluted to a volume of 1.19 L and a concentration of 6.00 M . What was the initial concentration? Expr

marysya [2.9K]

The initial concentration was 8.45M

Step 1: Given data

Initial concentration (C₁): ?

Initial volume (V₁): 635 mL = 0.845 L

Final concentration (C₂): 6.00 M

Final volume (V₂): 1.19 L

Step 2: Calculate the initial concentration

We have a concentrated NaCl solution and we want to prepare a diluted one. We will use the dilution rule.

C₁ × V₁ = C₂ × V₂

C₁ = C₂ × V₂ / V₁

C₁ = 6.00 M × 1.19 L / 0.845 L

C₁ = 8.45 M

Thus, The initial concentration was 8.45M

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7 0

2 years ago

Hi! I could use some help, I need to turn this in today

TiliK225 [7]

Explanation:

The nomenclature of ionic compounds is given by:

1. Positive is written first. And if the metal atom has various oxidation states then its oxidation state is to be mentioned in brackets with help of roman numbers

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

1.) : Calcium chloride (Correct)

In the given compound, calcium has oxidation state of +2 and chlorine has oxidation state of -1.The name is correct.

2.) : Copper (II) oxide (Incorrect)

In the given compound,copper has the oxidation state of +1 and oxygen has oxidation state of -2.So ,the correct name will be Copper (I) oxide.

3.) : Lead (II) sulfide (Incorrect)

In the given compound, lead has the oxidation state of +4 and sulfur has oxidation state of -2. So ,the correct name will be Lead (IV) sulfide.

3 0

3 years ago

15.35 L of gas is at a pressure of 198.0 kpa. At what pressure would the gas have a volume of 13.78

Ivahew [28]

Answer:

P₂ = 220.56KPa

Explanation:

Boyles Law P ∝ 1/V => Inverse relationship => Decreasing Volume => Increasing Pressure.

P₁ = 198 KPa P₂ = ?

V₁ = 15.35 Liters V₂ = 13.78 Liters

P₁V₁ = P₂V₂ => P₂ = P₁(V₁/V₂) = 198KPa(15.35 L/ 13.78L) = 220.6KPa

5 0

3 years ago

how many grams of calcium chloride arw produced from 10 grams of calcium oxide reacting wity an excessnof hydrochloric acid. CaO

Liono4ka [1.6K]

CaCO3 is the reactant in excess. The amount of CaCO3 remaining is 11.5 g . ... Hydrochloric acid and calcium chloride. 2 mol HCl1 CaCl2. Determine the mass of CaCO3 that reacted with the limiting reactant HCl .

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4 years ago