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3 years ago

What mixture can be separated by using a filter?

Chemistry

1 answer:

nexus9112 [7]3 years ago

4 0

<h2>Answer: </h2>

Option 2nd - a mixture of solid particles in a liquid.

<h2>Explanation: </h2>

For a Mixture of two immiscible liquids (for example water and oil) it is not possible to filter them with a filter as both of the liquid will pass through it.
For a mixture of a solid and a liquid (for example sand and water) it can be easily separated through a filter as on filtration solid will be left on the filter and the liquid will pass through it.
For a mixture of two miscible liquids (for example milk and water) both of them will form a single identity, and on filtration both of them will pass through the filter. Hence it is not possible to separate them through filter.
For a mixture of liquid and gas (for example drinking soda or Pepsi) filter is not needed for their separation as it will be separated when exposed in air.

Result: Option 2 is the correct answer.

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Concentration of solution in chloroform = $90$ ( moles of chloroform )

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$K_D =$ Concentration of solution in chloroform / Concentration of solution in water

Meaning;

$K_D = \frac{\frac{mole\ of\ chloroform}{volume\ of\ chloroform} }{\frac{mole\ of\ water}{volume\ of\ water} }$

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Now, we substitute our given values into the equation

$10 = \frac{\frac{90}{volume\ of\ chloroform} }{\frac{10}{volume\ of\ water} }\\\\10 *\frac{10}{volume\ of\ water} = \frac{90}{volume\ of\ chloroform} \\\\\frac{100}{volume\ of\ water} = \frac{90}{volume\ of\ chloroform}\\\\\frac{volume\ of\ chloroform}{volume\ of\ water} = \frac{90}{100}\\\\ \frac{volume\ of\ chloroform}{volume\ of\ water} = \frac{9}{10}\\\\ \frac{volume\ of\ chloroform}{volume\ of\ water} = 9:10$

Therefore, the relative volumes of chloroform and water that should be used is 9:10

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