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2 years ago

I’ll really appreciate it if you help me out on this one .

Chemistry

1 answer:

Westkost [7]2 years ago

5 0

1.
-Water levels are dangerously high for wildlife and humans.
-Animals seem to be lost, like the cow and the sheep especially.

2.
-There are not many trees near the water, meaning less areas for wildlife to live.
-There is not much wildlife in general.

Inferences
1. The wildlife shown will move relocate and adapt to another area.
2. Industry — emissions are visible in top left— will continue to hurt the environment. CO2 emissions will increase.

Good luck!

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What type of hydrocarbon is 2-octene, and what about the structure allows 2-octene to be classified as this type of hydrocarbon?

12345 [234]

an alkene because there is a double bond

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3 years ago

A copper atom has a mass of 1 06 times 10^-22 g and a penny has a mass of 2.5 g. Use this information to answer the questions be

amm1812

Answer:

Mass of 1 mole of copper is 63.83 g.

0.03916 moles of copper atoms have a mass equal to the 2.5 grams of copper penny.

Explanation:

Mass of 1 copper atom,m = $1.06\times 10^{-22} g$

$1 mole = 6.022\times 10^{23} atoms$

Mass of 1 mole of copper :

= $6.022\times 10^{23} atoms\times 1.06\times 10^{-22} g=63.83 g$

Mass of 1 mole of copper = 63.83 g

Mass of copper penny = 2.5 g

Atomic mass of copper = 63.83 g/mol

Moles of copper in 2.5 g of copper penny:

$\frac{2.5 g}{63.83 g/mol}=0.03916 mol$

0.03916 moles of copper atoms have a mass equal to the 2.5 grams of copper penny.

8 0

3 years ago

Sam places 5 g of baking soda in 5 g of liquid vinegar, and notices fizzing. After all the fizzing stops, 5 g of liquid remains.

anygoal [31]

Answer: G

5+5=10

10-5=5

5 g of gas escaped

3 0

2 years ago

Read 2 more answers

Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a tank

Masja [62]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The concentration equilibrium constant is $K_c = 14.39$

Explanation:

The chemical equation for this decomposition of ammonia is

$2 NH_3$ ↔ $N_2 + 3 H_2$

The initial concentration of ammonia is mathematically represented a

$[NH_3] = \frac{n_1}{V_1} = \frac{29}{75}$

$[NH_3] = 0.387 \ M$

The initial concentration of nitrogen gas is mathematically represented a

$[N_2] = \frac{n_2}{V_2}$

$[N_2] = 0.173 \ M$

So looking at the equation

Initially (Before reaction)

$NH_3 = 0.387 \ M$

$N_2 = 0 \ M$

$H_2 = 0 \ M$

During reaction(this is gotten from the reaction equation )

$NH_3 = -2 x$ (this implies that it losses two moles of concentration )

$N_2 = + x$ (this implies that it gains 1 moles)

$H_2 = +3 x$ (this implies that it gains 3 moles)

Note : x denotes concentration

At equilibrium

$NH_3 = 0.387 -2x$

$N_2 = x$

$H_2 = 3 x$

Now since

$[NH_3] = 0.387 \ M$

$x= 0.387 \ M$

$H_2 = 3 * 0.173$

$H_2 = 0.519 \ M$

$NH_3 = 0.387 -2(0.173)$

$NH_3 = 0.041 \ M$

Now the equilibrium constant is

$K_c = \frac{[N_2][H_2]^3}{[NH_3]^2}$

substituting values

$K_c = \frac{(0.173) (0.519)^3}{(0.041)^2}$

$K_c = 14.39$

3 0

2 years ago

1. Write the balanced chemical equation for the synthesis of magnesium phosphide from its elements, including the word “energy”

Evgen [1.6K]

Answer:

3Mg(s) +2P(s) -------> Mg3P2(s) + energy

Keq= [Mg3P2]/[Mg]^3 [P]^2

Explanation:

The equation for the formation of magnesium phosphide from its elements is;

3Mg(s) +2P(s) -------> Mg3P2(s) + energy

Hence we can see that three moles of magnesium atoms combines with two moles of phosphorus atoms to yield one mole of magnesium phosphide. The equation written above is the balanced chemical reaction equation for the formation of the magnesium phosphide.

The equilibrium expression for the reaction K(eq) will be given by;

Keq= [Mg3P2]/[Mg]^3 [P]^2

8 0

3 years ago