1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
erik [133]
3 years ago
13

If m RQ = 118°, then T = _____ degrees S = ______ degrees

Mathematics
2 answers:
Sati [7]3 years ago
8 0
59 degrees t and s are the same because they share an arch and angle is half of the circle length 118/2=59
Murrr4er [49]3 years ago
3 0
<span>t = 1/2mRQ
  = 1/2 (118)
  = 59 degrees

s = t  
   = 59 degrees</span>
You might be interested in
Let f(x)=(8x^4-3)^3 and g(x)=8x^4-3 given that f(x)=(h g)(x) , find h(x)
Harman [31]

<u>Answer:</u>

h(x) = x^{3}

<u>Step-by-step explanation:</u>

f(x) = (8 \times x^{4}- 3)^{3} ------------(1) (given)

g(x) =(8 \times x^{4}- 3) -------------(2) (given)

so,

f(x) = h(g(x)) (given)

    = (g(x))^{3}-----(from (1) and (2))

⇒h(k) = k^{3}-----(taking g(x) = k)

⇒h(x) = x^{3} is the function.

8 0
3 years ago
92÷9−5=913 find value of p
Vlad [161]

Answer:

which p? there isn't any p in above equation

3 0
2 years ago
Due for 10:00am need help​
Sveta_85 [38]

Answer:

y=9b to the second power t over m

Step-by-step explanation:

should look like this

y=9b^2t/m

6 0
3 years ago
The length of a table is 6 feet. On a scale drawing, the length is 2 inches. Write three possible scales for the drawing.
Rus_ich [418]
A possible scale for the drawing can be 
1 inches : 3 feet.
2 inches : 6 feet 
or 3 inches to 9 feet
or 0.5 inches to 1.5 feet.

Hope this helps :)
6 0
3 years ago
In RSM camp, there are four counselors for every fifty seven students and three teachers for every five counselors.
Ray Of Light [21]

Answer:

Students : Counselors : Teachers = 285: 20 : 12

Step-by-step explanation:

In the camp, the ratio of:

( C: S )  Counselors : Students   is  4   :  57

( T: C )  Teachers :   Counselors  is  3   :  5

To determine the ratio of   -  Students : Counselors : Teachers

Here given      -  C : S  = 4 : 57

Multiplying both sides by 5, we get

C: S  = 4 x 5  : 57 x 5  = 20 : 285

So, for every 20 counselors, there are 285 students      ...... (1)

Similarly, given   Teachers :   Counselors  is  3   :  5

Multiplying both sides by 4, we get

T  : C  = 3 x 4  : 5 x 4  = 12  : 20

So, for every 12  teachers, there are 20 Counselors      ...... (2)

Hence, in both equation 1 and 2 the number of counselors is same = 20 .

Hence, both the ratios acne be combined.

So we get C : S  = 20 : 285      and T : C  = 12: 20

Inverting the values

⇒  S : C  = 285 : 20         and C : T  = 20 : 12

or, S : C : T  = 285: 20 : 12

or, Students : Counselors : Teachers = 285: 20 : 12

Hence, for every 285 students there are 20 counselors and 12 teachers.

4 0
3 years ago
Other questions:
  • Find the circumference of P. Leave your answer in terms of pi. The radious is 5 in.
    11·2 answers
  • the number of bacteria in a container increases at the rate of R(t) bacteria per hour. If there are 1000 bacteria at time t=0 ,
    14·1 answer
  • 11a-8b-9a-3b=
    13·1 answer
  • 20 people show up to a post-PSTAT 120A party. If everyone shakes hands with everyone else, how many handshakes take place
    13·1 answer
  • Elisondra is eating at a restraurant with three friends. They want to choose at random who will order first. If you
    12·1 answer
  • QUICK PLEASE ILL MARK BRAINLIEST (PRETEST: FUNCTIONS - PLATO EDMENTUM)
    11·2 answers
  • If the relationship is proportional, what is the missing value from the table?
    14·1 answer
  • Gym A charges $60 a month plus $4 per visit. The monthly cost at Gym B is represented by y = 4x + 50, where x is the number of v
    5·1 answer
  • G(x) = -x2 + 24<br> For the function g defined above, what is the value of<br> g(-4)?
    9·2 answers
  • A certain brand of crackers costs $2.89 for 12.4 ounces.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!