I think it is A. not sure though
The formula for the area of a circle is
A=πr²
plug in the data we know
A=π4²
A=16π
Since we only we need to find the area of the shaded section, we need to twerk this equation a bit. (remember that the shaded section is 84/360 of the original circle.)
A=84/360*16π
A=11.728
A=11.73 units²
answer: <span>A=11.73 units²</span>
The answer is 6x^2+11x-35
Answer: see below
<u>Step-by-step explanation:</u>
1) 10, 2, 1.2, 1.12, 1.112, 1.1112

t₁ = 10
t₂ = 10/10 + 1 = 2
t₃ = 2/10 + 1 = 1.2
t₄ = 1.2/10 + 1 = 1.12
t₅ = 1.12/10 + 1 = 1.112
t₆ = 1.112/10 + 1 = 1.1112
2) 10, 2, -2, -4, -5, -5.5, ...

t₁ = 10
t₂ = 10/2 - 3 = 2
t₃ = 2/2 - 3 = -2
t₄ = -2/2 - 3 = -4
t₅ = -4/2 - 3 = -5
t₆ = -5/2 - 3 = -5.5
Answer:
D .8
Step-by-step explanation:
hypotenuse (h) = 10
base (b) = 6
perpendicular (p) = a= ?
We know by using Pythagoras theorem we get
p = √ h² - b²
a = √ 10² - 6²
a = √ 64
a = 8
Hope it will help :)