An 89 kg person climbs up a uniform 13 kg ladder. The ladder is 5.9 m long; its lower end rests on a rough horizontal floor (sta
tic friction coefficient 0.26) while its upper end rests against a frictionless vertical wall. The angle between the ladder and the horizontal is 52◦. Let d denote the climbing person's distance from the bottom of the ladder (see the above diagram). When the person climbs too far (d > dmax), the ladder slips and falls down (kaboom!). Calculate the maximal distance dmax the person will reach before the ladder slips. The acceleration of gravity is 9.8 m/s2.
1 answer:
You might be interested in
The height, h to which the package of mass m bounces to depends on its initial velocity, v and the acceleration due to gravity, g and is given below:
Perfectly elastic collisions are collisions in which the momentum as well as the energy of the colliding bodies is conserved.
In perfectly elastic collisions, the sum of momentum before collision is equal to the momentum after collision.
Also, the sum of kinetic energy before collision is equal to the sum of kinetic energy after collision.
Since some of the Kinetic energy is converted to potential energy of the body;
Therefore, the height to which the package m bounces to depends on its initial velocity and the acceleration due to gravity.
Learn more about elastic collisions at: brainly.com/question/7694106