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spayn [35]
3 years ago
8

How much ancient plant debris is necesary to form one foot of coal A.one foot of plant debris B.ten feet of plant debris c.50 fe

et of plant debris d.one hundred feet of plant debris.
Physics
2 answers:
Roman55 [17]3 years ago
6 0
The correct answer is B 
kirill115 [55]3 years ago
5 0
I think it is b i hope it helps
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What is the acceleration of a ball that has dropped from a six-story building​
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Answer:

Because the ball is dropped, we are going to assume its initial velocity is 0. With that said, acceleration is essentially the change in the velocity versus the change in time, hence the unit m/s^2, which can be thought of as “meters per second per second.” The only force acting on the ball is gravity.

That being said, you can simply divide the change in velocity by the change in time, giving you an answer of 9.8 m/s^2, which is the value of g. Even if they did not give you a time, the answer would still always be the value of g (that is if the question pertains to earth), as acceleration due to gravity is a constant.

Explanation:

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What is population density?
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Quiz Review Problems
zlopas [31]

The momentum of a neutron p = 586.25 kg m / s.

<u>Explanation:</u>

The product of mass and the velocity gives the momentum of an object and it is a vector quantity. It is denoted by the letter p. The unit of momentum is kilogram meter per second (or) kg m / s.

Given mass m = 1.675 \times 10,            velocity v = 3.500 \times 10

                  Momentum, p = mv

where m represents the mass,

          v represents the velocity.

                   momentum p = (1.675 \times 10) \times (3.500 \times 10)

                   momentum p = 586.25 kg m / s.

5 0
3 years ago
A grocery cart with a mass of 15 kg is pushed at constant speed along an aisle by a force fp = 12 n which acts at an angle of 17
Korolek [52]

<span>Given:

Mass of cart: 15kg</span>

Aisle length = 14m

Angle = 17° below the horizontal

Force fp = 12 N

 

So, the solution would be like this for this specific problem:

 

<span><span>1)    </span>W(by applied force) = F(applied) x s x cosθ <span>
=>W(a) = 12 x 14 x cos17* = 160.66 J </span></span>
<span><span>
2)    </span>By F(net) = F(applied) - F(friction) <span>
=>As v = constant => a = 0 => F(net) = 0 
=>F(applied) = F(friction) 
<span>=>W(friction) = -F(friction) x s
=>W(friction) = -F(applied) x s 
=>W(f) = -12 x 14 x cos17* = -160.56 J </span></span></span>
<span><span>
3)    </span>0, as the displacement is perpendicular to Force </span>
<span><span>
4)    </span>0, as the displacement is perpendicular to Force</span>  
<span>
To add, the force that is applied<span> to an object by a person or another object is called the applied force.</span></span>
8 0
3 years ago
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