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2 years ago

Suppose the collision between the packages is perfectly elastic. To what height does the package of mass m rebound?

1 answer:

7 0

The height, h to which the package of mass m bounces to depends on its initial velocity, v and the acceleration due to gravity, g and is given below:

$h = \frac{v^{2}}{2g}$

<h3>What are perfectly elastic collision?</h3>

Perfectly elastic collisions are collisions in which the momentum as well as the energy of the colliding bodies is conserved.

In perfectly elastic collisions, the sum of momentum before collision is equal to the momentum after collision.

Also, the sum of kinetic energy before collision is equal to the sum of kinetic energy after collision.

Since some of the Kinetic energy is converted to potential energy of the body;

$\frac{mv^{2}}{2} = mgh$

$h = \frac{v^{2}}{2g}$

Therefore, the height to which the package m bounces to depends on its initial velocity and the acceleration due to gravity.

Learn more about elastic collisions at: brainly.com/question/7694106

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During a neighborhood baseball game in a vacant lot, a particularly wild hit sends a 0.148 kg baseball crashing through the pane

LiRa [457]

Answer:

Explanation:

mass of baseball, m = 0.148 kg

initial velocity, u = 15.5 m/s

final velocity, v = 10.1 m/s

Impulse is defined as the change in momentum of the body.

Impulse = change in momentum

I = m (v - u)

I = 0.148 (10.1 - 15.5)

I = - 0.8 Ns

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3 years ago

Explain e pieces of evedince

olasank [31]

Evidence is <span>the facts or information that shows and supports a statement. WIth evidence, you can prove that what you say is true/valid.</span>

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3 years ago

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How much space does 1kg of air occupy? <br><br> The density of the air is 0.0013g/mL

nexus9112 [7]

The basic relationship between mass m, volume V and density d is given by
$d= \frac{m}{V}$
re-arranging the equations and using m=1 kg and $d=0.0013 g/mL = 0.0013 kg/L$ , we find the volume:
$V= \frac{m}{d}= \frac{1 kg}{0.0013 kg/L}=769.2 L$
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3 years ago

What was the average speed for the second leg of the trip? help me im stuck

SVEN [57.7K]

Answer:

The average speed on the second leg of the trip is 2 m/s

Explanation:

Notice that the second leg of the trip is from 8 m in the horizontal axis heading to the left to position 4 m. So the velocity is going to be negative and given by the quotient of the change in position (-4 m) divided by the time it took: 2 seconds.

This gives: -4/ 2 m/s = -2 m/s

But the speed is going to be the absolute value of the velocity, that is:

2 m/s

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3 years ago

In one or two sentences make and justify a claim about two aspects of the picture that illustrate behaviors of light.

Studentka2010 [4]

We can make the claim that light can be reflected, which is justified by the reflection seen on the water as well as the colors seen in the photo.

<h3>How can we tell that light is being reflected?</h3>

We can claim that light can and is being reflected in this image due to the reflection in the water as well as the colors. As the light traveling in the air collides with the water, it abruptly changes speed, causing a portion of these waves to be reflected back, thus creating a mirror image on the surface of the water. This is also the case with colors, which are caused by a material reflecting all but one wavelength of light.

Therefore, we can confirm that it is possible to make the claim that light can be reflected, which is justified by the reflection seen on the water as well as the colors seen in the photo.

To learn more about how light behaves visit:

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2 years ago